Ruby Koans' Greed Task

Question

Having coded in Java and C# for quite some years, I'm currently learning Ruby. I'm working my way through the Ruby Koans tutorial. At some point, you are to implement a method that calculates the game-score of a dice-game called Greed.

I came up with this recursive Java/C#-like method. It passes all the supplied unit tests, so technically it's correct.

Now I'm wondering: Is this good Ruby code? If not, how would a "Rubyist" write this method? And possibly: Why? I'm also not so happy about the amount of duplicate code but can't think of a better Rubyish way.

def score(dice)   #dice is an array of numbers, i.e. [3,4,5,3,3]
  return 0 if(dice == [] || dice == nil)

  dice.sort!

  return 1000 + score(dice[3..-1]) if(dice[0..2] == [1,1,1])
  return 600 + score(dice[3..-1]) if(dice[0..2] == [6,6,6])
  return 500 + score(dice[3..-1]) if(dice[0..2] == [5,5,5])
  return 400 + score(dice[3..-1]) if(dice[0..2] == [4,4,4])
  return 300 + score(dice[3..-1]) if(dice[0..2] == [3,3,3])
  return 200 + score(dice[3..-1]) if(dice[0..2] == [2,2,2])
  return 100 + score(dice[1..-1]) if(dice[0] == 1)
  return 50 + score(dice[1..-1]) if(dice[0] == 5)
  return 0 + score(dice[1..-1]);
end

Some background (if needed)

# Greed is a dice game where you roll up to five dice to accumulate
# points. A greed roll is scored as follows:
#
# * A set of three ones is 1000 points
#
# * A set of three numbers (other than ones) is worth 100 times the
#   number. (e.g. three fours is 400 points).
#
# * A one (that is not part of a set of three) is worth 100 points.
#
# * A five (that is not part of a set of three) is worth 50 points.
#
# * Everything else is worth 0 points.
#
#
# Examples:
#
# score([1,1,1,5,1]) => 1150 points
# score([2,3,4,6,2]) => 0 points
# score([3,4,5,3,3]) => 350 points
# score([1,5,1,2,4]) => 250 points
#
# More scoring examples are given in the tests below:


class AboutScoringProject < EdgeCase::Koan
  def test_score_of_an_empty_list_is_zero
    assert_equal 0, score([])
  end

  def test_score_of_a_single_roll_of_5_is_50
    assert_equal 50, score([5])
  end

  def test_score_of_a_single_roll_of_1_is_100
    assert_equal 100, score([1])
  end

  def test_score_of_a_single_roll_of_1_is_100
    assert_equal 200, score([1,1])
  end

  def test_score_of_multiple_1s_and_5s_is_the_sum_of_individual_scores
    assert_equal 300, score([1,5,5,1])
  end

  def test_score_of_single_2s_3s_4s_and_6s_are_zero
    assert_equal 0, score([2,3,4,6])
  end

  def test_score_of_a_triple_1_is_1000
    assert_equal 1000, score([1,1,1])
  end

  def test_score_of_other_triples_is_100x
    assert_equal 200, score([2,2,2])
    assert_equal 300, score([3,3,3])
    assert_equal 400, score([4,4,4])
    assert_equal 500, score([5,5,5])
    assert_equal 600, score([6,6,6])
  end

  def test_score_of_mixed_is_sum
    assert_equal 250, score([2,5,2,2,3])
    assert_equal 550, score([5,5,5,5])
  end

  def test_score_of_a_triple_1_is_1000A
    assert_equal 1150, score([1,1,1,5,1])
  end

  def test_score_of_a_triple_1_is_1000B
    assert_equal 350, score([3,4,5,3,3])
  end

  def test_score_of_a_triple_1_is_1000C
    assert_equal 250, score([1,5,1,2,4])
  end
end

Answer 1

There are a few issues with the code:

1. Do not check for == nil when it is not specified as a valid value for the method. Here,checking for it and returning 0 might mask another problem.
2. Do not use return statements unless necessary. In ruby, almost everything is an expression, and methods return the value of the last expression. Here you can use if...elsif, or case instead of a series of if statement.
3. Do not modify parameters that come into your function (dice.sort!).
4. Do not use recursion if it makes the code less readable.

Here is a version of the code with the advice above applied:

def score(dice)
  score = 0
  counts = dice.each_with_object(Hash.new(0)) { |x, h| h[x] += 1 }
  (1..6).each do |i|
    if counts[i] >= 3 
      score += (i == 1 ? 1000 : 100 * i)
      counts[i] = [counts[i] - 3, 0].max
    end
    score += counts[i] * (i == 1 ? 100 : 50)
  end
  score
end

Answer 2

@glebm has some very good points. I want to also introduce a different style. Here is how I would approach this problem.

def score dice
  dice.group_by(&:to_i).inject(0) do |score, combo| 
    score + combos_score(*combo) + ones_score(*combo) + fives_score(*combo)
  end
end

def combos_score dice_value, dice_with_value
  number_of_bonues = [dice_with_value.size - 2, 0].max

  bonus_for(dice_value) * number_of_bonues
end

def bonus_for dice_value
  dice_value == 1 ? 1000 : dice_value * 100
end

def ones_score dice_value, dice_with_value
  return 0 if dice_value != 1 || dice_with_value.size > 2

  dice_with_value.size * 100
end

def fives_score dice_value, dice_with_value
  return 0 if dice_value != 5 || dice_with_value.size > 2

  dice_with_value.size * 50
end

I like that

1. Logic for each scoring scenario is isolated together
2. There isn't a need to build a special Hash that would calculate the score.
3. Use of the built in Enumerable#group_by to grab similar die together
4. Small methods that are easy to test