# Showing the even numbers between two numbers which the user has entered

I've done it to be honest, but I feel like I'm writing extra code. I want a shortcut.

The code is:

let num1 = +prompt("enter a number");
let num2 = +prompt("enter a number");

if(isNaN(num1) || isNaN(num2) || num1 == num2) {
} else{
let smallnum = 0, bignum = 0;
if (num1 > num2){
smallnum = num2;
bignum= num1;
} else{
smallnum = num1;
bignum = num2;
}
i = smallnum + 1;
while(i < bignum){
if (i % 2 == 1){
i++;
console.log(i);
} else {
console.log(i);
}
i += 2;
}
}


Please tell me whether I've written well or not.

• You can use max and min to get the lowest and highest number.

• You can also use the check for even or not even only on the start.

• If you wrap it in a function, you can end earlier and clean up the if statement

 let num1 = +prompt("Enter a number");
let num2 = +prompt("Enter another number");

printEvenNumber(num1, num2);

function printEvenNumber(num1, num2) {
// Exit early
if (isNaN(num1) || isNaN(num2) || num1 === num2) {
return false;
}
// Use min and max
let smallnum = Math.min(num1, num2);
let bignum = Math.max(num1, num2);

// Start from the next even number after smallnum
let start = smallnum % 2 === 0 ? smallnum + 2 : smallnum + 1;

for (let i = start; i < bignum; i += 2) {
console.log(i);
}
}


If smallnum is even and bignum is the next even number, then the code will print out bignum which is not between the two numbers.