4
\$\begingroup\$

I've been working on a regex-based UK postcode validation and format correction tool - with the aim of creating a list of postcodes that can be readily geocoded. The variety of postcode formats is explained here. I have based my regex on a discussion here.

My correction tool is designed to cope with a number of commonly made mistakes when a postcode is inputted in a free text format as such:

  • Postcode entered in lower case
  • No space between first and second half of postcode
  • O instead of 0 in two key areas e.g. CH6O 8MG -> CH60 8MG & M8 OFG -> M8 0FG

I have managed this (somewhat clunky) here:

pc<-data.frame(postcode=c("GIR 0AA","M2 0AB","M2 OAB","M2 0ab","M1 1AA","M11AA","M60 1NW","M6O 1NW","M601NW","CR2 6XH","CR26XH","DN55 1PT","DN551PT","W1A 1HQ","W1A1HQ","w1a 1hq","EC1A 1BB","EC1A1BB"), true=c(TRUE,TRUE,FALSE,FALSE,TRUE,FALSE,TRUE,FALSE,FALSE,TRUE,FALSE,TRUE,FALSE,TRUE,FALSE,FALSE,TRUE,FALSE))

#Identify postcodes not in correct format
pc$original_validate<-grepl('^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) [0-9][ABD-HJLNP-UW-Z]{2}))$',pc$postcode)
pc$non_pc<-ifelse(pc$original_validate ==FALSE,as.character(pc$postcode),"")

#Convert all to upper case
pc$new_pc<-toupper(pc$non_pc)

#Identify postcodes without a space and include a space
pc$non_pc2<-grepl('^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) [0-9][ABD-HJLNP-UW-Z]{2}))$',pc$new_pc)
pc$non_pc2<-ifelse(pc$non_pc2==FALSE & pc$new_pc!="",as.character(pc$new_pc),"")
pc$new_pc2<-gsub("^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y])))))([0-9][ABD-HJLNP-UW-Z]{2})$","\\1 \\9",pc$non_pc2)
pc$non_pc<-NULL
pc$non_pc2<-NULL

#Identify postcodes containing an O instead of 0 in first half
pc$non_pc3<--grepl('^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) [0-9][ABD-HJLNP-UW-Z]{2}))$',pc$new_pc2)
pc$non_pc3<-ifelse(pc$non_pc3==FALSE & pc$new_pc2!="",as.character(pc$new_pc2),"")
pc$new_pc3<-gsub("([A-Z][0-9][O]|[A-Z][A-Z][O]|[A-Z][A-Z][0-9][O])","\\10",pc$non_pc3)
pc$new_pc3<-gsub("O0","0",pc$new_pc3)

 #Identify postcodes containing an O instead of 0 in second half 
 pc$non_pc4<-grepl('^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) [0-9][ABD-HJLNP-UW-Z]{2}))$',pc$new_pc3)
pc$non_pc4<-ifelse(pc$non_pc4==FALSE & pc$new_pc3!="",as.character(pc$new_pc3),"")  
 pc$new_pc4<-gsub("^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))))) ([O][ABD-HJLNP-UW-Z]{2})$", "\\1 0\\9",pc$non_pc4)
pc$new_pc4<-gsub("0O","0",pc$new_pc4)
pc$non_pc3<-NULL
pc$non_pc4<-NULL

#Combine pc's into one column of correctly formated postcodes
pc$total<-paste(pc$postcode,pc$new_pc,pc$new_pc2,pc$new_pc3,pc$new_pc4)
pc$correct_pc<-str_extract(pc$total,"((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) [0-9][ABD-HJLNP-UW-Z]{2}))")
pc$new_pc<-NULL
pc$new_pc2<-NULL
pc$new_pc3<-NULL
pc$new_pc4<-NULL
pc$total<-NULL

#Validate
pc$correct_validate<-grepl('^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) [0-9][ABD-HJLNP-UW-Z]{2}))$',pc$correct_pc)

With the results like so:

pc
postcode  true original_validate correct_pc correct_validate
 GIR 0AA  TRUE              TRUE    GIR 0AA             TRUE
  M2 0AB  TRUE              TRUE     M2 0AB             TRUE
  M2 OAB FALSE             FALSE     M2 0AB             TRUE
  M2 0ab FALSE             FALSE     M2 0AB             TRUE
  M1 1AA  TRUE              TRUE     M1 1AA             TRUE
   M11AA FALSE             FALSE     M1 1AA             TRUE
 M60 1NW  TRUE              TRUE    M60 1NW             TRUE
 M6O 1NW FALSE             FALSE    M60 1NW             TRUE
  M601NW FALSE             FALSE    M60 1NW             TRUE
 CR2 6XH  TRUE              TRUE    CR2 6XH             TRUE
  CR26XH FALSE             FALSE    CR2 6XH             TRUE
DN55 1PT  TRUE              TRUE   DN55 1PT             TRUE
 DN551PT FALSE             FALSE   DN55 1PT             TRUE
 W1A 1HQ  TRUE              TRUE    W1A 1HQ             TRUE
  W1A1HQ FALSE             FALSE    W1A 1HQ             TRUE
 w1a 1hq FALSE             FALSE    W1A 1HQ             TRUE
EC1A 1BB  TRUE              TRUE   EC1A 1BB             TRUE
 EC1A1BB FALSE             FALSE   EC1A 1BB             TRUE

Whilst this does work fine, as you can see it takes a slightly torturous way to get there! I was wondering if anyone has any suggestions about improving the efficiency of this process? It would be great to get a single function that achieves every correction; however, my function writing skills are pretty poor!

\$\endgroup\$

1 Answer 1

3
\$\begingroup\$

My first suggestion is to write a is_valid function since you are using this code in quite a few places:

is_valid <- function(x)
   grepl('^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) [0-9][ABD-HJLNP-UW-Z]{2}))$', x)

Then, it is also a good idea to write a separate function for each of the fixes you have. It makes your code easier to test and reuse. Also, when using appropriate function names, it makes your code self-explanatory and can replace all the comments:

fix_case <- toupper

fix_space <- function(x)
   sub("^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y])))))([0-9][ABD-HJLNP-UW-Z]{2})$","\\1 \\9", x)

fix_zero_1 <- function(x)
   sub("([A-Z][0-9]|[A-Z][A-Z]|[A-Z][A-Z][0-9])[O]","\\10", x)

fix_zero_2 <- function(x) {
   x <- sub("^((GIR 0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))))) ([O][ABD-HJLNP-UW-Z]{2})$", "\\1 0\\9", x)
   sub("0O", "0", x)
}

With these, your code can simplify to:

postcodes <- c(
  "GIR 0AA",
  "M2 0AB",
  "M2 OAB",
  "M2 0ab",
  "M1 1AA",
  "M11AA",
  "M60 1NW",
  "M6O 1NW",
  "M601NW",
  "CR2 6XH",
  "CR26XH",
  "DN55 1PT",
  "DN551PT",
  "W1A 1HQ",
  "W1A1HQ",
  "w1a 1hq",
  "EC1A 1BB",
  "EC1A1BB"
)

bg <- postcodes
bg <- ifelse(is_valid(bg), bg, fix_case(bg))
bg <- ifelse(is_valid(bg), bg, fix_space(bg))
bg <- ifelse(is_valid(bg), bg, fix_zero_1(bg))
bg <- ifelse(is_valid(bg), bg, fix_zero_2(bg))

data.frame(original   = postcodes,
           best_guess = bg,
           is_valid   = is_valid(bg))

Note how I am using vectors everywhere and only in the end putting the results in a data.frame. Indeed, there is arguably no need for a data.frame until you want to see the results in a nice format, at the very end. Keeping things in vectors avoid the repetitive pc$ and the annoying conversion from character vectors to factors (what forced you to use as.character).

I have slightly modified your algorithm, where instead of replacing valid postcodes by "" so they won't get affected by fixes, I am propagating a vector of valid or "best guess" codes (bg) via the construct:

bg <- ifelse(is_valid(bg), bg, som_fix(bg))

It is shorter this way and removes the need for the error-prone paste() at the end of your code.

\$\endgroup\$
4
  • \$\begingroup\$ Beautifully done, thanks! Definitely see your point over vector vs. dataframe - nearly all my work is done in dataframes, so I don't tend to think of other data structures potentially making my life easier! \$\endgroup\$ Commented Jan 25, 2016 at 10:11
  • \$\begingroup\$ Quick add on - I have been working on an extended version of your code encompassing more common mistakes (will post as answer when complete)... As I haven't seen anything like this available as a completed function my intention is to publish it somewhere like R-Bloggers for future use (code review doesn't get very high footfall) 1. would you be ok with this? 2. How do you want me to acknowledge you? \$\endgroup\$ Commented Jan 25, 2016 at 12:02
  • \$\begingroup\$ Thanks for asking, but feel free to publish however you like. There is no need to acknowledge me, or you can just say "a user on CodeReview". \$\endgroup\$
    – flodel
    Commented Jan 26, 2016 at 12:39
  • \$\begingroup\$ Cheers! Should be a useful tool for people \$\endgroup\$ Commented Jan 26, 2016 at 14:27

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.