Design a pattern using python

Question

I want to print the below pattern

* 
* *
* * *
* * * *
* * * * *

My logic written

for row in range(1,6):
  for col in range(1,6):
    if row is col:
      print(row * '* ')

Can someone review the code and suggest any improvements needed

The code which i have written is it a right approach ?

Answer 1

Welcome to Code Review.

Your code is literally 4 lines. So there isn't much to review.

• Do not use the is operator to compare the integers. See difference between is and ==

• You can save the nested loop: you are already ensuring col == row so you can instead write:

for row in range(1,6):
    print("* " * row)

• If we want to get technical, the code you have written has a time complexity of O(n^3), but the problem can be solved in O(n^2). You can read more on this topic here.