Non-recursive factorial in Ruby

Question

I've implemented a factorial function in a more "Ruby" way. I would like to get feedback on the algorithm.

def factorial_of n
  (1..n).inject :*
end

factorial_of 5
=> 120

Answer 1

The "of" in the name factorial_of is redundant and unconventional.

factorial_of 0 returns nil instead of the correct answer, which is 1.

def factorial(n)
  (1..n).inject(1, :*)
end