Creating json objects with undefined properties

Question

I have the following snippet code which, within a loop, creates a JavaScript object where some of the properties maybe undefined:

reader.on('record', function(record) {

    let p = record.children;
    let player = {};

    // below we create a dynamic key using an object literal obj['name'], this allows use to use
    // the id as the firebase reference id.
    player[p[0].text] = {
        id: parseInt(p[0].text, 10) || "",
        name: p[1].text || "",
        country: p[2].text || ""
    };
};

My question therefore; is there a better way for creating this object via a 'Map' for example? If the properties are undefined then do not add them to the object.

Note: This data is being sent to a Firebase DB, so any undefined values throw an error -- my crude (but working) approach is to add them as an empty string.

Here is a sample of the JSON I would like to see (notice country is not missing from the second player):

{
 "players" : {
    "100001" : {
      "id" : 100001,
      "name" : "Matt Webb",
      "country" : "ENG"
    },
    "100002" : {
      "id" : 100002,
      "name" : "Joe Bloggs",
    }
}

Answer 1

To make your code a bit more accurate you could run a function before every call to firebase (this is the main reason you need it) and create a new object with only defined props

function getDefinedProps(obj) {
  var o = {}
  for (key in obj) {
    if (obj[key] !== undefined)
      o[key] = obj[key]
  }

  return o;
}

Answer 2

JSON.stringify() seems to do exactly what you need.

It will remove all functions and all undefined variables.

a = { b : undefined , c : 'inited'};
JSON.stringify( a )

will return

'{"c":"inited"}'

If you need the object itself, you can JSON.parse the resulting string to go back to a clean object.