I agree 100% with @ingo-burk's answer. Here are a few points on top of that.

You could load the paths from a .properties file quite easily, for example given a properties file on the classpath:

# config.properties
paths = C:/xampp/xampp-control.exe|C:/Program Files/xampp/xampp-control.exe|C:/Program Files (x86)/xampp/xampp-control.exe

and this Java code:

private static final String PROPERTIES_FILENAME = "player.properties";
private static final String PATHS_PROPERTY = "paths";
private static final String ITEM_SEPARATOR = "|";

private String[] getPaths(String filename, String propName) throws IOException {
    InputStream input = this.getClass().getClassLoader().getResourceAsStream(filename);
    if (input == null) {
        return new String[0];
    }
    Properties prop = new Properties();
    prop.load(input);
    input.close();
    return prop.getProperty(propName, "").split(ITEM_SEPARATOR);
}

private String[] getPaths(String filename) throws IOException {
    return getPaths(filename, PATHS_PROPERTY);
}

String[] getPaths() throws IOException {
    return getPaths(PROPERTIES_FILENAME, PATHS_PROPERTY);
}

Notice that I changed all the path separators from \\ to /. Java figures out the correct path separator in the operating system, and it's simpler to type this way.

Btw, if the executable is always called xampp-control.exe then perhaps you can put that name in its own property, and remove the duplication from paths.

I agree 100% with @ingo-burk's answer. Here are a few points on top of that.

You could load the paths from a .properties file quite easily, for example given a properties file on the classpath:

# config.properties
paths = C:/xampp/xampp-control.exe|C:/Program Files/xampp/xampp-control.exe|C:/Program Files (x86)/xampp/xampp-control.exe

and this Java code:

private static final String PROPERTIES_FILENAME = "player.properties";
private static final String PATHS_PROPERTY = "paths";
private static final String ITEM_SEPARATOR = "|";

private String[] getPaths(String filename, String propName) throws IOException {
    InputStream input = this.getClass().getClassLoader().getResourceAsStream(filename);
    if (input == null) {
        return new String[0];
    }
    Properties prop = new Properties();
    prop.load(input);
    input.close();
    return prop.getProperty(propName, "").split(ITEM_SEPARATOR);
}

private String[] getPaths(String filename) throws IOException {
    return getPaths(filename, PATHS_PROPERTY);
}

String[] getPaths() throws IOException {
    return getPaths(PROPERTIES_FILENAME, PATHS_PROPERTY);
}

Notice that I changed all the path separators from \\ to /. Java figures out the correct path separator in the operating system, and it's simpler to type this way.

Btw, if the executable is always called xampp-control.exe then perhaps you can put that name in its own property, and remove the duplication from paths.