I agree 100% with [@ingo-burk][1]'s answer. Here are a few points on top of that.

You could load the paths from a `.properties` file quite easily, for example given a properties file on the classpath:

    # config.properties
    paths = C:/xampp/xampp-control.exe|C:/Program Files/xampp/xampp-control.exe|C:/Program Files (x86)/xampp/xampp-control.exe

and this Java code:

    private static final String PROPERTIES_FILENAME = "player.properties";
    private static final String PATHS_PROPERTY = "paths";
    private static final String ITEM_SEPARATOR = "|";

    private String[] getPaths(String filename, String propName) throws IOException {
        InputStream input = this.getClass().getClassLoader().getResourceAsStream(filename);
        if (input == null) {
            return new String[0];
        }
        Properties prop = new Properties();
        prop.load(input);
        input.close();
        return prop.getProperty(propName, "").split(ITEM_SEPARATOR);
    }

    private String[] getPaths(String filename) throws IOException {
        return getPaths(filename, PATHS_PROPERTY);
    }

    String[] getPaths() throws IOException {
        return getPaths(PROPERTIES_FILENAME, PATHS_PROPERTY);
    }

Notice that I changed all the path separators from `\\` to `/`. Java figures out the correct path separator in the operating system, and it's simpler to type this way.

Btw, if the executable is always called `xampp-control.exe` then perhaps you can put that name in its own property, and remove the duplication from `paths`.


  [1]: https://codereview.stackexchange.com/users/41406/ingo-burk