I don't know if I'm wording the problem correctly in the title. Basically, in a chess board, I need to find the diagonals a bishop can move on, and more specifically, the coordinates of those squares. So, given a grid of any size and a position in that grid (expressed in coordinates within the grid), I have to compute the coordinates of the diagonals of that initial position. I'm using zero-based indexing, and the `(row, column)` notation for coordinates. For example, on a 8x8 grid, with starting position of `(0, 0)`, the returned list should be `[(0, 0), (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6), (7, 7)]`. On a 8x8 grid, with starting position of `(3, 4)`, the returned list should be `[(3, 4), (2, 3), (1, 2), (0, 1), (4, 5), (5, 6), (6, 7), (4, 3), (5, 2), (6, 1), (7, 0), (2, 5), (1, 6), (0, 7)]` This is my working program in Python 3: def diagonals(coord, size): limit = size - 1 coords = [coord] row = coord[0] col = coord[1] while row > 0 and col > 0: row -= 1 col -= 1 coords.append((row, col)) row = coord[0] col = coord[1] while row < limit and col < limit: row += 1 col += 1 coords.append((row, col)) row = coord[0] col = coord[1] while row < limit and col > 0: row += 1 col -= 1 coords.append((row, col)) row = coord[0] col = coord[1] while row > 0 and col < limit: row -= 1 col += 1 coords.append((row, col)) return coords coord = (3, 4) size = 8 print(diagonals(coord, size)) Depending on the diagonal (4 cases), row and column are added or subtracted by one until the last square is reached, and everything is kept in a list, which in the end is returned. It works, but it left me wondering if there's a simpler, different, better way of doing this, probably using linear algebra or something? And how about idiomatically, how can this be more Pythonic?