Task: Complete the following function that determines if the number of even and odd values in an integer
list is the same. The function would return true if the list contains 5, 1, 0, 2 (two evens and two odds),
but it would return false for the list containing 5, 1, 0, 2, 11 (too many odds). The function should
return true if the list is empty, since an empty list contains the same number of evens and odds (0 for
both). The function does not affect the contents of the list.

My code:

```
def balanced(lst):
    n = len(lst)
    if n % 2 != 0:
        return False
    if n % 2 == 0:
        count_1 = 0
        count_2 = 0
        for item in lst:
            if item % 2 == 0:      #even
                count_1 += 1
            if item % 2 != 0:       #odd
                count_2 += 1
    if count_1 == count_2:
        return True
    else:
        return False
def result(lst):
     if balanced(lst):
         print("Your list is successfully balanced! It has same number of evens and odds!!")
     else:
         print("Oh no! Sorry! Your list seems to be not balanced! Try another list please!")
def main():
     lst_1 = [1,2,3,5,6,8,5,9]
     lst_2 = []
     lst_3 = [2,4,5,7]
     lst_4 = [1,2,4,4]
     lst_5 = [1,2,3]
     result(lst_1)
     result(lst_2)
     result(lst_3)
     result(lst_4)
     result(lst_5)
main()


```