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Quentin Pradet
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  • There's a lot of duplication to get src, name, and so on. Simply use $.map:

      var properties = $.map(["src", "name", "date", "desc"], function(id) {
        return xml.getElementsByTagName(id)[d].childNodes[0].nodeValue;
      }
    
  • Don't forget any var

  • Create img using this less error-prone technique:

      var img = $('<img>').attr('alt', name).attr('src', src);
    
Quentin Pradet
  • 6.9k
  • 1
  • 24
  • 44