This algorithm will work perfectly fine for what you want to develop:
Before that, let me make it clear that if you want to check double repeatitions of characters same number of times, you have to run a `for loop` in reverse to identify the 2nd character. So if the 2nd character is not same as the first one identified, and if it's number of repeatitions are the same, you print both the characters or else, just print the single character you find at the first for loop.

    public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);
		System.out.println("Enter String 1: ");
		String A1 = sc.nextLine();
		
		MaxRepeat(A1);
    }
    
	public static void MaxRepeat(String A) {
		int count = 1;
		int max1 = 1;
		char mostrepeated1 = ' ';
		for(int i = 0; i < A.length()-1;i++) {
			char number = A.charAt(i);

			if(number == A.charAt(i+1)) {
				count++;
				if(count>max1) {
					max1 = count;
					mostrepeated1 = number;
				}
				continue;
			}
				count = 1;
		}
		
		count = 1;
		int max2 = 1;
		char mostrepeated2 = ' ';
		for(int i = A.length()-1; i>0; i--) {
			char number = A.charAt(i);

			if(number == A.charAt(i-1)) {
				count++;
				if(count>max2) {
					max2 = count;
					mostrepeated2 = number;
				}
				continue;
			}
				count = 1;
		}
		
		if((max1==max2) && (mostrepeated1==mostrepeated2)) {
			System.out.println("Most Consecutively repeated character is: " + mostrepeated1 + " and is repeated " + max1 + " times.");
		}
		
		else if((max1==max2) && (mostrepeated1!=mostrepeated2)) {
			System.out.println("Most continously repeated characters are: " + mostrepeated1 + " and " + mostrepeated2 + " and they are repeated " + max1 + " times");
		}
	}