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It is a set of edges of a graph given. An edge is given as an array of its endpoints, e.g. [:a, :b]. The array can contain an arbitrary amount of endpoints. Therefore [] and [:b, :c, :d] are also valid edges.

I want to find all islands which means that I looking for unconnected sets of nodes. Here is my Ruby solution.

e = [[:a, :b],[:c, :d],[:b, :c, :e], [:f, :g]]
n = e.flatten.uniq

def islands(edges)
  edges.reduce([]) do |islands, edge|
    matches = islands.select { |island| island.any? { |node| edge.include?(node) } }

    if !matches.empty?
      island = matches.shift
      islands.delete_if { |i| matches.include?(i) }

      island.concat(matches.flatten)
      island.concat(edge)
      island.uniq!
    else
      islands << edge
    end

    islands
  end
end

puts islands(e).inspect
# => [[:a, :b, :c, :d, :e], [:f, :g]]

Is there room for improvement?

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1 Answer 1

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if !matches.empty? 

equals

if matches.any?

And the second is preferable, cause you don't have negation.

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  • \$\begingroup\$ [nil].empty? == [nil].any? \$\endgroup\$
    – Nakilon
    Aug 6, 2015 at 20:03

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