Idiomatic Ruby FizzBuzz

Question

Can anyone offer any criticism on the following at a simple FizzBuzz in terms of Ruby idioms or otherwise?

class FizzBuzz

  def initialize(fizz = 'Fizz', buzz = 'Buzz')
    @fizz = fizz
    @buzz = buzz
  end

  def is_number_divisible_by?(number, divisor)
    number % divisor == 0
  end

  def get_text(number)
    fizz_buzz_text = ''
    if is_number_divisible_by?(number, 3)
      fizz_buzz_text += @fizz
    end
    if is_number_divisible_by?(number, 5)
      fizz_buzz_text += @buzz
    end
    return fizz_buzz_text
  end

end

fb = FizzBuzz.new
(1...101).each do |i|
  fb_text = fb.get_text(i)
  puts fb_text.empty? ? i : fb_text
end

Answer 1

First off: If you want a range that goes from 1 to x, inclusive, write (1..x), not (1...x+1).

Second, if it's the last line executed in a method, it's automatically returned -- so in get_text, you don't need return in the last line, just the actual code.

Also, get_text should return the text to be printed, not what it might be. Move the empty check (fb_text.empty ? i : fb_text) to get_text instead of having it at the puts call. See the code at the end for clarification.

if statements with just one line should be expressions at the end. Again, see the modified code for what I mean.

Methods defined in a class are generally talking about the object they're run on. I'd pull is_number_divisible_by? out of the class and dropping it at the beginning of your code instead, and renaming it to something like divisible_by? instead (since it's shorter and carries the same information).

Aside from that (and an odd extra newline at the beginning of your class definition), it looks good! Here's your code with these suggestions:

def divisible_by?(number, divisor)
  number % divisor == 0
end

class FizzBuzz
  def initialize(fizz = 'Fizz', buzz = 'Buzz')
    @fizz = fizz
    @buzz = buzz
  end

  def get_text(number)
    fizz_buzz_text = ''
    fizz_buzz_text += @fizz if divisible_by? number, 3
    fizz_buzz_text += @buzz if divisible_by? number, 5
    fizz_buzz_text.empty? ? number : fizz_buzz_text
  end

end

fb = FizzBuzz.new
(1..100).each do |i|
  puts fb.get_text i
end

Note: Personally, I wouldn't do this in an OOP way. Ruby is much more oriented towards functional programming, though of course OOP is perfectly valid; besides, functional is a bit simpler. My preferred way to do it would be something like this:

(1..100).each do |num|
  output = ''
  output += 'Fizz' if num % 3 == 0
  output += 'Buzz' if num % 5 == 0
  puts output.empty? ? num : output
end

Answer 2

QPaysTaxes has a lot of great points, but one thing that stands out is that you are asking for the "Idiomatic" way of doing things in ruby. For fizzbuzz, that would involve a hash mapping numbers to words so you could easily and arbitrarily extend it. I would rewrite QPaysTaxes get_text function as such to get more idiomatic ruby:

# in class FizzBuzz
TEXT = {
  3 => "Fizz",
  5 => "Buzz",
  # 7 => "Jazz",
  # 11 => "Guzz",
} # or set this dynamically during initialization, whatever

def get_text(number)
  fizz_buzz_text = TEXT.inject("") do |str, rule|
    number % rule[0] == 0 ? str + rule[1] : str 
  end

  fizz_buzz_text.empty? ? number : fizz_buzz_text 
end

Now you can uncomment those extra rules or throw your own in with ease. If the method for determining replacement or not changes from being num divisible by rule to ((num * 6) + 4) is divisible by rule, you only need to change a single location instead of once per rule. (This practice is called DRY, or "Don't Repeat Yourself".)

I can explain the code further if you want, just leave a comment below.