# Speeding up Python date conversion function currently using list comprehension and datetime

I am reading a large data file where the time is given in number of days since some epoch. I am currently converting this to Python's datetime format using this function:

import datetime as dt
def days2dt(days_since_epoch):
epoch = dt.datetime(1980, 1, 6)
datelist = [epoch + dt.timedelta(days=x) for x in days_since_epoch]
return datelist

# run with sample data (might be larger in real life, in worst case multiply
# the list by 40 instead of 6)
import numpy as np
sample = list(np.arange(0, 3/24., 1/24./3600./50.))*6
dates = days2dt(sample)


Running this function takes 5x longer than reading the entire file using pandas.read_csv() (perhaps because the listcomp performs an addition for each element). The returned list is used immediately as the index of the pandas DataFrame, though interestingly, using a generator expression instead of a listcomp as above improves performance by ~35% (why?).

Aside from using a generator expression, can the performance of this function be improved in any way, e.g. by not performing this date conversion per-element or by using some NumPy feature I'm not aware of?

• Do you have example input (in size and distribution)? Jan 15, 2015 at 20:37
• @Veedrac See the updated question. The data come from GPS satellites, let's say they are 50 Hz resolution and the satellite is visible for 3 hours 2 times a day. Then the example code I added would be 3 days of data from one satellite (the values would of course not be repeated like that in real life, but the example gives the correct amount of data as well as the fact that they are not entirely contiguous). Jan 15, 2015 at 21:16

You should try Numpy's datetime and timedelta support:
def days2dt(days_since_epoch):

Note that 90% of the time taken for days2dt is converting the input list to a numpy.array; if you pass in a numpy.array it goes much faster. Nevertheless, this is significantly faster than the list comprehension already.