# Common calculator, birth date calculator, units converter, and data recorder

I am very (very) new to programming, and today I (semi-)successfully wrote my first program that performs very basic things.

My hope is that I can receive some constructive criticism around how I structured it all and if I am doing things in the most efficient and proper way possible for what I am trying to achieve.

#include <cstdio>
#include <cstdlib>
#include <iostream>
#include <fstream>
#include <windows.h>
using namespace std;

void calculator();
void birthcal();
void convert();
void recorddata();

int main()
{
for ( int choice = 0;; )
{
cout << "Please choose one of the following:\n1. Common Calculator\n2. Birth Date Calculator\n3. Convert units of measurement\n4. Read/ Record data to file\n5. Convert Celsius to Fahrenheit\n\nChoice: ";
cin >> choice;
cout << endl;

if (choice == 1)
{
calculator();
break;
}

if (choice == 2)
{
birthcal();
break;
}

if (choice == 3)
{
convert();
break;
}

if (choice == 4)
{
break;
}

if (choice == 5)
{
temperature();
break;
}

else
{
cin.clear();
cin.get();
system("PAUSE");

continue;
}

return 0;
}

}
void temperature()
{
int celsius;
cout << "Enter the temperature in Celsius: ";
cin >> celsius;
int factor;
factor = 212 - 32;
int fahrenheit;
fahrenheit = factor * celsius/100 + 32;
cout << "Fahrenheit value is: ";
cout << fahrenheit << endl;
system("PAUSE");

}

void calculator()
{
int number1, number2, result;
for ( ;; )
{
cout << "Welcome to Calculator" << endl;
cout << "Valid operators are +, -, x, /" << endl;
cout << "Please enter an equation: ";

char sign(1);

cin >> number1 >> sign >> number2;

if (sign == '+')
{
result = number1 + number2;
break;
}

if (sign == '-')
{
result = number1 - number2;
break;

}
if (sign == 'x')
{
result = number1 *  number2;
break;
}
if (sign == '/')
{
result = number1 / number2;
break;
}

else
{
cin.clear();
cin.get();
system("PAUSE");
continue;
}
}
}

void birthcal()
{
int age, birthdate, year;
year = 2014;
for ( ;; )
{
cout << "Welcome to the Birth Year calculator" << endl;
cin >> age;
if ( age > 0 && age < 200 )
{
birthdate = year - age;

cout << "\nYou were likely born in the year " << birthdate << " or " << birthdate-- << endl;

break;
}

else
{

cout << "Invalid age, please try again \n" << endl;
cin.clear();
cin.get();
system("PAUSE");
continue;
}
}
}
void convert()
{

int convertchoice;

for ( convertchoice = 0;; )
{

cout << "Welcome to the Units Converter \nPlease pick:\n\n1.Centimeters to Inches \n2.Inches to Centimeters\n\nChoice: ";
cin >> convertchoice;
if (convertchoice == 1)
{
int cm, in, factor = 2.54;

cout << "Please enter number in Centimeters: ";
cin >> cm;

in = cm / factor;

cout << "The result is: " << in << endl;

system("PAUSE");

break;
}

if (convertchoice == 2)
{

int cm, in, factor = 2.54;

cout << "Please enter the number in Inches: ";
cin >> in;

cm = in * factor;

cout << "The result is: " << cm << endl;

break;
}

else
{

cin.clear();
cin.get();
system("PAUSE");

continue;
}

}
}

{

for ( int choice = 0;; )
{
ofstream myfile;

cin >> choice;

if (choice == 1)
{
recorddata();
break;
}

if (choice == 2)
{
break;
}
else
{

cin.clear();
cin.get();
system("PAUSE");
continue;

}

}}

void recorddata()
{
char name[10], location[15], colour[10], fruit[10];
int age;

cout << " - Recording Data - \n\n";

ofstream myfile;
myfile.open ("info.txt");
if (myfile.is_open())
{
cin.getline (name, 10);
cin >> name;
myfile << "Name: " << name << endl;
cin >> age;
myfile << "Age: " << age << endl;
cout << "\nCountry:\n\n";
cin.getline(location, 15);
cin >> location;
myfile << "Location: " << location << endl;
cin.getline(colour, 10);
cin >> colour;
myfile << "Favourite Colour: " << colour << endl;
cin.getline(fruit, 10);
cin >> fruit;
myfile << "Favourite Fruit: " << fruit << endl;

cout << "/n/nThank You for entering the information";

system("PAUSE");

}
}

{
cout << " - Reading Data - \nNow we will read data from the file.\n\n";
string line;
ifstream myfile ("example.txt");
if (myfile.is_open())
{
while ( getline (myfile,line))
{
cout << line << '\n';
}
}
}

• Will first fix the indentation. Its hard to read. Second get rid of multiple empty lines. May 10, 2014 at 6:46

## Use consistent indenting

How your code is formatted has a big impact on how readable it is to others and even to yourself. Pick a style that you find readable and use it consistently.

## Add missing temperature() declaration

I couldn't compile your program at first because the declaration of the temperature() routine was missing.

## Search for and eliminate unused variables

In the calculator() function, the code sets the value of result but then doesn't do anything with it. I suspect you intended to print the result. Unused variables in code are generally a bad sign, but most compilers will locate them for you and point them out. Learn how to activate that feature of your compiler and use it.

## Fix the use of else

In an if .. else clause, the else only "attaches" to the most recent if so in your calculator function, the else at the bottom is only evaluated if the sign is not / which is probably not really what you intended. That whole series of if .. else is probably better expressed as a switch statement instead:

switch (sign) {
case '+':
result = number1 + number2;
break;
case '-':
result = number1 - number2;
break;
case 'x':
result = number1 *  number2;
break;
case '/':
result = number1 / number2;
break;
default:
std::cout << "Sorry, I don't know the " << sign <<
" operator.\n"
"I only know operators '+', '-', 'x' and '/'\n";
std::cin.clear();
std::cin.get();
}
std::cout << "Result = " << result << '\n';


This same comment applies to almost all the other places you've used a compound if statement, but I'll discuss the whole issue of a menu object below. You'll note that I made a few other changes, which I'll mention below.

## Don't abuse using namespace std

Putting using namespace std at the top of every program is a bad habit that you'd do well to avoid.

Let's say I've typed "5 * 3" into your calculator expecting it to calculate the number 15. Instead the program will tell me "You have made a mistake, please try again." which is not at all helpful and puts the blame on the user rather than the program. I reworded it instead to look like this:

std::cout << "Sorry, I don't know the " << sign << " operator.\n"
"I only know operators '+', '-', 'x' and '/'\n";


## Use appropriate data types

The program uses int data types in a number of places that float or double might be more appropriate. Specifically, the temperature and calculator are arguable cases, but it's definitely the case for your convert function which includes the line:

int cm, in, factor = 2.54;


This doesn't do what you think it does. Specifically, it will create the float literal "2.54" then convert it to the integer "2" and then assign that value to factor. These should be declared float rather than int for the program to make any sense.

Even if nobody else ever looks at your code, there is a benefit in making the structure of the code neat and clear. For instance, in the convert() function, you have the conversion factor defined in two different places and with a fixed number. Does the value change from iteration to iteration? If the number were typed incorrectly, it would have to be changed two places which makes no sense. Finally, it isn't something that should be modified, so it should be declared const. I would probably write it like this:

// number of centimeters per inch, according to the
// U.S. National Institute of Standards and Technology
const float CM_PER_INCH = 2.54;


That does three things. It tells what the constant is, tells why the original programmer thinks it should have the value it does and gives a strong hint to experienced programmers that this is a constant by making the name all UPPER CASE. This is an old convention that dates back many decades ago when such things would have been defined in C code using #define because the language didn't originally have const.

## Use std::string rather than plain old char[]

In your recorddata function, you have this line:

char name[10], location[15], colour[10], fruit[10];


My full name is longer than 10 characters, so it won't fit. There doesn't seem to be a compelling reason to truncate it since you're using delimiters in the resulting file, so all of these would be better as std::string.

## Fix use of std::getline

Your recorddata function currently includes this:

    cout << "Your Name:\n\n";
cin.getline (name, 10);
cin >> name;


You don't really want both of those lines. What your program should probably do is to just use the std::cin >> name function and declare name as std::string.

The recorddata function includes this:

cout << "/n/nThank You for entering the information";


Those aren't newline characters at the beginning of that string.

## Use a menu object or at least a common menu function

In a number of places in your code, you have something like a menu. Your code presents a couple of options and then asks the user to pick one based on an input number. Rather than repeating that code in many places, it would make sense to make it generic. Only the prompt strings actually change, but the underlying logic of presenting the choices and asking for input are all the same. It looks like you're a beginning programmer, and so perhaps you haven't learned about objects yet, but this kind of repeated task with associated data is really well-suited to object-oriented programming and that's something that C++ is very good at expressing.

## Learn the subtle parts of the language

The birthcal routine has a couple of problems, including a fixed, hardcoded year, but I'm only going to point out one of the more subtle errors. The code includes this line:

cout << "\nYou were likely born in the year " << birthdate << " or " << birthdate-- << endl;


It will probably work, but you should know that the result of birthdate-- may be undefined. It's because the order of evaluation within this line is not defined by the standard. Technically we talk about sequence points within the code, and you can read all about it here.

The fix is quite simple here. Just change that to birthdate-1. Also, while you're in there, wouldn't birthyear be a more accurate name for that variable?

• Wow, Excellent! Can't thank you enough for taking the time to help me. Cheers!
– Cam
May 10, 2014 at 19:00
• I had trouble when trying to implement the time.h library to determine the current year. I couldn't get it to work properly.
– Cam
May 10, 2014 at 19:21
• FYI, sequence points are no longer current with C++11. The current wording is a bit less confusing. @Cam The basic idea is this: When you call a function e.g. Foo(Bar(), Baz()); it is not guaranteed that Bar() will be evaluated before Baz() (or vice versa). So you can't write int bar = 1; Foo(bar--, bar); because you never know whether you'll decrement bar before or after you evaluate the second argument; your call could be Foo(1, 1) or Foo(1, 0) (in fact this is technically undefined behavior, so the compiler is free to do either of these things or really anything else).
– ruds
May 14, 2014 at 6:54

A couple of other things:

When you're coding a menu it's much more readable to put each item on a separate line. This also gives you a clearer idea of what the menu will look like when the program runs:

cout << "Please choose one of the following:\n";
cout << "1. Common Calculator\n";
cout << "2. Birth Date Calculator\n";
cout << "3. Convert units of measurement\n";
cout << "4. Read/ Record data to file\n";
cout << "5. Convert Celsius to Fahrenheit\n\n";
cout << "Choice: ";


Whenever you have repeating blocks of code it's good practice to use a sub routine:

void DisplayError(string errormsg)
{
cout << errormsg << "\n";
cin.clear();
cin.get()
}


To replace this code:

cout << "Invalid age, please try again \n" << endl;
cin.clear();
cin.get();


Use:

DisplayError("Invalid age, please try again");


Try to avoid the use of system("PAUSE"). It's considered unsafe since the definition for PAUSE can be redefined outside of the program to do anything.

• Considering how you've structured this "DisplayError" function, where would it be most appropriate to define the contents of the errormsg string? within the function itself?
– Cam
May 13, 2014 at 23:42
• Not sure what you meant by defining the contents. The function is about eliminating code duplication. In your code there are several spots where a call to this function will replace several lines of code in each spot. I added more code to clarify a bit. If you want greater functionality for determining the type of error perhaps an enum and a switch block would help.
– user33306
May 14, 2014 at 1:00
• Okay, that clears it up. I wasn't so sure how I might change the string according to each different error. Excuse me while I bother you for some more information... But how would I implement the switch block in this circumstance? Enum's are new to me, but after some light reading I think I understand better. Although, I'm trying to understand the difference between a const int and an enum. I imagine there is likely a vast difference. :P
– Cam
May 14, 2014 at 4:43
• An enum is basically a list of constants, each one identified with a readable name. for instance Invalid_Input could be error 1. But a year from now you might have trouble remembering what error 1 is but seeing it passed as Invalid_Input would be easier to figure out.
– user33306
May 14, 2014 at 5:05
1. Fix indentation (at any block, indent once)
2. I like infinite while loops instead of infinite for loops (personal preference)
3. I don't believe you need the breaks, you can replace them with an if/else if/else if/else
4. Consider a switch statement instead of the ifs (personal preference)
5. Code safety (validate input parameters)