I'm writing a little Downloader that will look through directories online and download the content. The first prototype of my program is a success, now I just want to refine it and learn some more C#. The task is this:

Take this string:


and create the substring between the last two /

Result: All%20Ends%20In%20Silence

I find my current code brutish and probably not a clean, C# way of solving the problem:

    string GetDirectoryName(string directory)
        int lastIndex  = directory.LastIndexOf("/");
        int count = directory.Count<char>(elem => elem == '/') - 1;

        int startIndex = 0;
        while (count > 0)
            startIndex = directory.IndexOf("/", startIndex) + 1;

        return directory.Substring(startIndex, lastIndex - startIndex).Replace("%20", " ");

Please advise me how I could make this code cleaner, clearer and following the C# methodology of programming.


The .NET framework will do this for you pretty cleanly with the right classes.

For example:

string url = "http://example.free.pl/plus%20violent/Dark%20The%20Suns/All%20Ends%20In%20Silence/";

DirectoryInfo di = new DirectoryInfo( new Uri(url).LocalPath );

The di.Name property contains "All Ends In Silence".

  • \$\begingroup\$ That's pretty useful. I'll have to look at the library on MSDN, thanks! \$\endgroup\$ – IAE Sep 20 '11 at 15:27

You could replace your loop with a call to LastIndexOf:

const char separator = '/';
int lastSlash = directory.LastIndexOf(separator);
int slashBeforeLast = directory.LastIndexOf(separator, lastSlash - 1);
return directory.Substring(slashBeforeLast + 1, lastSlash - slashBeforeLast - 1);
  • \$\begingroup\$ I am already getting the last '/' with LastIndexOf. How would a second call to LastIndexOf get me the other '/' I need? \$\endgroup\$ – IAE Sep 21 '11 at 15:45
  • \$\begingroup\$ @SoulBeaver: By adding an index. I've specifically linked to the overload that takes an index. I'm updating my answer with an example. \$\endgroup\$ – Hosam Aly Sep 21 '11 at 21:00
  • \$\begingroup\$ Aaaah now I understand what you mean, thanks! \$\endgroup\$ – IAE Sep 22 '11 at 10:49

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