Script to stop a program after a certain amount of time

Question

I created this script because the Spotify desktop app doesn't have a built in sleep timer, and I needed one. I made it as easy to use as possible, and it can close other programs because it asks for the package name at the beginning of the script.

import time
import sys
import subprocess

pkgname = input("Please set the package name: ")
tillclose = float(input("\nPlease choose the amount of time before it closes:\n\n[1.] 10 Minutes\n[2.] 30 Minutes\n[3.] 1 Hour\n[4.] 2 Hours\n[5.] 3 Hours\n[6.] 4 Hours\n[7.] 5 Hours\n"))

if tillclose == 1:
    print("Confirmed. Set to close in 10 Minutes.")
    tillclose = 600

    for remaining in range(int(tillclose), 0, -1):
        sys.stdout.write("\r")
        sys.stdout.write("{:2d} seconds remaining.".format(remaining))
        sys.stdout.flush()
        time.sleep(1)

    subprocess.call(["taskkill", "/F", "/IM", pkgname])

elif tillclose == 2:
    print("Confirmed. Set to close in 30 Minutes.")
    tillclose = 1800

    for remaining in range(int(tillclose), 0, -1):
        sys.stdout.write("\r")
        sys.stdout.write("{:2d} seconds remaining.".format(remaining))
        sys.stdout.flush()
        time.sleep(1)

    subprocess.call(["taskkill", "/F", "/IM", pkgname])

elif tillclose == 3:
    print("Confirmed. Set to close in 1 Hour.")
    tillclose = 3600

    for remaining in range(int(tillclose), 0, -1):
        sys.stdout.write("\r")
        sys.stdout.write("{:2d} seconds remaining.".format(remaining))
        sys.stdout.flush()
        time.sleep(1)

    subprocess.call(["taskkill", "/F", "/IM", pkgname])

elif tillclose == 4:
    print("Confirmed. Set to close in 2 Hours.")
    tillclose = 7200

    for remaining in range(int(tillclose), 0, -1):
        sys.stdout.write("\r")
        sys.stdout.write("{:2d} seconds remaining.".format(remaining))
        sys.stdout.flush()
        time.sleep(1)

    subprocess.call(["taskkill", "/F", "/IM", pkgname])

elif tillclose == 5:
    print("Confirmed. Set to close in 3 Hours")
    tillclose = 10800

    for remaining in range(int(tillclose), 0, -1):
        sys.stdout.write("\r")
        sys.stdout.write("{:2d} seconds remaining.".format(remaining))
        sys.stdout.flush()
        time.sleep(1)

    subprocess.call(["taskkill", "/F", "/IM", pkgname])

elif tillclose == 6:
    print("Confirmed. Set to close in 4 Hours")
    tillclose = 14400

    for remaining in range(int(tillclose), 0, -1):
        sys.stdout.write("\r")
        sys.stdout.write("{:2d} seconds remaining.".format(remaining))
        sys.stdout.flush()
        time.sleep(1)

    subprocess.call(["taskkill", "/F", "/IM", pkgname])

elif tillclose == 7:
    print("Confirmed. Set to close in 5 Hours")
    tillclose = 18000

    for remaining in range(int(tillclose), 0, -1):
        sys.stdout.write("\r")
        sys.stdout.write("{:2d} seconds remaining.".format(remaining))
        sys.stdout.flush()
        time.sleep(1)

    subprocess.call(["taskkill", "/F", "/IM", pkgname])

else:
    print("Invalid option, please run again.")

It works flawlessly, but I'm wondering if there's a shorter way to make it.

Answer 1

import time
import sys
import subprocess

pkgname = input("Please set the package name: ")
choice = float(input("\nPlease choose the amount of time before it closes:\n\n[1.] 10 Minutes\n[2.] 30 Minutes\n[3.] 1 Hour\n[4.] 2 Hours\n[5.] 3 Hours\n[6.] 4 Hours\n[7.] 5 Hours\n"))

secs_in_hour = 60 * 60
hour_intervals = [1/6, 1/2, 1, 2, 3, 4, 5]
# choice - 1 for options {1, 2, 3, 4, 5, 6, 7} to index transition
tillclose = hour_intervals[int(choice) - 1] * secs_in_hour
for remaining in range(int(tillclose), 0, -1):
    sys.stdout.write("\r")
    sys.stdout.write("{:2d} seconds remaining.".format(remaining))
    sys.stdout.flush()
    time.sleep(1)

subprocess.call(["taskkill", "/F", "/IM", pkgname])