1
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In such an array:

$arr = Array (
    [key0] => Array (
        [subkey0] => Array (
            [0] => "value0"
            [1] => "value1"
        )
        [subkey1] => Array (
            [0] => "value0"
            [1] => "value1"
        )
    )
    [key1] => Array (
        [subkey0] => Array (
            [0] => "value0"
            [1] => "value1"
        )
        [subkey1] => Array (
            [0] => "value0"
            [1] => "value1"
        )
    )
)

In order to add $varX to the end of $arr[keyX][subkeyX] as [X] => $varX, I use, inside a loop, the following:

$arr[$key] = array(
    "subkey0" => array_merge((array)$arr[$key]["subkey0"], (array)$var1),
    "subkey1" => array_merge((array)$arr[$key]["subkey1"], (array)$var2)
    ...
)

And I might be working with even more nested arrays, so I was wondering if there was a way for subkey0 to refer to itself, or if I could do something like:

"subkeyX" =>+ (array)$varX

Or use array_merge() in a different way to add $varX to the end of subkeyX as [X] => $varX.

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3
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I don't know if I understand the question right. But this should work.

foreach ($keys as $key) {
    $arr2[$key]['subkey0'][] = $var1;
    $arr2[$key]['subkey1'][] = $var2;
}
| improve this answer | |
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  • \$\begingroup\$ Thanks but it does not seem to work. For instance, check this phpfiddle -- click on run to see the results. \$\endgroup\$ – Alex Mar 30 '13 at 1:11
  • \$\begingroup\$ Sorry, my answer was not clear enough. I edited it. \$\endgroup\$ – AlucardTheRipper Mar 30 '13 at 1:54

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