I would like to reduce the following Python code. I have one list and a few if statements.

a=[one, two, three, four]
if a[0] in b:
if a[1] in b:
if a[2] in b:
if a[3] in b:

How can I reduce this to two lines of code and still to run in sequence? It will permit list a to be of "n" length and I will not have to add them individually.

  • 4
    \$\begingroup\$ This does not have enough context to be on topic. What are you actually trying to do with your application? Can you show your whole program? \$\endgroup\$ – Reinderien Jun 28 at 1:04
  • 2
    \$\begingroup\$ print([a[(i+1)%len(a)] for i in range(len(a)) if a[i] in b]) \$\endgroup\$ – impopularGuy Jun 28 at 5:45

Firstly we can simply loop through a to get the values to check that are in b. However we need to know the index so we can increment a value, i, whilst looping through a.

i = 0
for value in a:
    if value in b:
        print(a[i + 1])
    i += 1

You should notice that this doesn't actually work. This is because on the last value of a we go out of bounds. To fix this we can simply use the modulo operator, %, to keep the value in bounds.

i = 0
for value in a:
    if value in b:
        print(a[(i + 1) % len(a)])
    i += 1

From here we can use enumerate rather than increment i manually. And we start i at 1 to remove the need for that (i + 1).

for i, value in enumerate(a, start=1):
    if value in b:
        print(a[i % len(a)])

From you have a couple of options.

  • You can use zip with itertools to remove the need for i % len(a). This isn't going to be nice to read but can be more performant.
  • Use a comprehension to reduce this to one line of code.

However these are more advanced topics.

| improve this answer | |
  • \$\begingroup\$ Thank you. But how can I do this in sequence? For example with a top "if" and keyboard confirmation. Press enter show first item then another enter the second etc? \$\endgroup\$ – Andy Andy Jun 28 at 11:13
  • \$\begingroup\$ @AndyAndy You have not coded that and so asking for that is off-topic and I will not answer. If you manage to do that by yourself then you can post a new question. \$\endgroup\$ – Peilonrayz Jun 28 at 11:15

Not the answer you're looking for? Browse other questions tagged or ask your own question.