# Python - Hexadecimal to Decimal conversions

I have written a python 2 program for a school project to convert from hexadecimal to decimal without using built-in functions and vice versa in python. I would like to know how I can make my code more concise - specifically, the "d_func" function.

d_dict = {"0" : 0, "1" : 1, "2" : 2, "3" : 3, "4" : 4, "5" : 5, "6" : 6, "7" : 7, "8" : 8, "9" : 9, "A" : 10, "B" : 11, "C" : 12, "D" : 13, "E" : 14, "F": 15}

def d_func(digit, mode):
if mode == 1:
for x in range(len(d_dict.keys())):
if digit == list(d_dict.keys())[x]:
return x
else:
for y in range(len(d_dict.values())):
if digit == list(d_dict.values())[y]:
return list(d_dict.keys())[y]

def hd_func(h_num):
d_num, p = 0, 0

for digit in range(len(h_num), 0, -1):
d_num = d_num + 16 ** p * d_func(h_num[digit - 1], 1)
p += 1

return str(d_num)

def dh_func(d_num):
f_list, h_num, p = [], "", 0

while d_num > 0:
f_list.append(d_num % 16)
d_num //= 16

for f in f_list[::-1]:
h_num += d_func(f, 2)

return h_num

func_dict = {"h": hd_func, "d": dh_func}
u_choice, u_num = input("Enter [H] for Hexadecimal to Decimal, [D] for Decimal to Hexadecimal"), input("Enter the number: ")
print(func_dict[u_choice.lower()](u_num))

• Please use python-3.x in the future, as python-2.x has reached it's end of life. – Linny Jan 17 at 22:04
• I use python 3 outside of school but my school uses an online version of python 2, so I am required to write and submit programs in python 2. – Mattthecommie Jan 17 at 22:07
• As long as you know to use python-3.x. :) – Linny Jan 17 at 22:07

First -- document your code! I read through your d_func function and here's my attempt at writing a docstring for what it does, with Python-2-compatible type hints. Hopefully I got it right. :)

def d_func(digit, mode):
# type: (Union[str, int], int) -> Union[int, str, None]
"""Mode 1: give the int value of the hex digit.
Other modes: give the hex digit of the given value.
Returns None if you give it a bad value, I guess?
"""
if mode == 1:
for x in range(len(d_dict.keys())):
if digit == list(d_dict.keys())[x]:
return x
else:
for y in range(len(d_dict.values())):
if digit == list(d_dict.values())[y]:
return list(d_dict.keys())[y]
return None  # stumblebum


Right off the bat: this should not be one function. (The fact that it can return either an int or a str depending on its input type is a good clue!) You should have one function that converts value to digit and another that converts digit to value; there's no value at all to having one function that does completely different things depending on a flag you pass it.

Second: yes, this can be a lot simpler. I think you could implement d_func as follows:

d_dict = {"0" : 0, "1" : 1, "2" : 2, "3" : 3, "4" : 4, "5" : 5, "6" : 6, "7" : 7, "8" : 8, "9" : 9, "A" : 10, "B" : 11, "C" : 12, "D" : 13, "E" : 14, "F": 15}
d_dict_reverse = {v: d for d, v in d_dict.iteritems()}  # this is just building a new dictionary with the keys and values swapped

def d_func(digit, mode):
# type: (Union[str, int], int) -> Union[int, str]
if mode == 1:
return d_dict[digit]
else:
return d_dict_reverse[digit]


At that point, it doesn't need to be a function at all, because you're just doing a simple dictionary lookup. Give your dictionaries reasonable names that say what they do:

digit_to_value = {
"0" : 0, "1" : 1, "2" : 2, "3" : 3, "4" : 4, "5" : 5, "6" : 6, "7" : 7,
"8" : 8, "9" : 9, "A" : 10, "B" : 11, "C" : 12, "D" : 13, "E" : 14, "F": 15
}
value_to_digit = {v: d for d, v in digit_to_value.iteritems()}


d_num = d_num + 16 ** p * d_func(h_num[digit - 1], 1)


do:

d_num = d_num + 16 ** p * digit_to_value[h_num[digit - 1]]


    for f in f_list[::-1]:
h_num += d_func(f, 2)


do:

    for f in f_list[::-1]:
h_num += value_to_digit[f]


With this approach, not only do you not have to write a function, but unlike your function the dictionary will automatically raise a KeyError if you provide the wrong kind of input, e.g. if you do value_to_digit[100] or digit_to_value[1]. Raising an error ASAP when you mess up (aka "fail fast") is good, because it makes it easier to figure out exactly where your bug is. :)

• d_func could be written in one line: return d_dict[digit] if mode else d_dict_reverse[digit] – Linny Jan 17 at 22:06

In addition to Sam I want to point out some other things

# Avoid typing long list/dict constants

Very often you can construct them by code, which is less error prone. Instead of

d_dict = {"0" : 0, "1" : 1, "2" : 2, "3" : 3, "4" : 4, "5" : 5, "6" : 6, "7" : 7, "8" : 8, "9" : 9, "A" : 10, "B" : 11, "C" : 12, "D" : 13, "E" : 14, "F": 15}


you do

import string

digit = dict(zip(range(16), string.digits + string.ascii_uppercase))
value = {v: k for k, v in digit.items()}


If you type all the values you have to write test cases for all of them.

# Loop like a pro

You prefer to loop like

for i in range(len(something)):
print(something[i])


That is not how it is done in Python as it is error prone. In Python you loop like

for e in something:
print(e)


If for some reason you really also need the index you use enumerate()

for i, e in enumerate(something):
print(i, e)


That said we change

def hd_func(h_num):
d_num, p = 0, 0

for digit in range(len(h_num), 0, -1):
d_num = d_num + 16 ** p * d_func(h_num[digit - 1], 1)
p += 1

return str(d_num)


to

def to_int(s):
i = 0
for c in s:
i = i*16 + value[c]
return i


The loop is much cleaner. By changing the algorithm I also got rid of the counter. Also I think returning a string is wrong here and I changed that to an int. Also I changed the function name to fit the return type and be less cryptic.

# Do not initialize as a tuple if it isn't one

f_list, h_num, p = [], "", 0


These variables do not form a natural tuple. Use three lines of code. Readability counts. Of course there is nothing wrong with initializing e. g. coordinates in a single line.

# Do initialize variables right before you need them

In the line

f_list, h_num, p = [], "", 0


the variable h_num is initialized at the beginning of the function while it is needed just before the second loop. Compare the readability of

def dh_func(d_num):
f_list, h_num, p = [], "", 0

while d_num > 0:
f_list.append(d_num % 16)
d_num //= 16

for f in f_list[::-1]:
h_num += d_func(f, 2)

return h_num


to

def dh_func(d_num):

f_list = []
while d_num > 0:
f_list.append(d_num % 16)
d_num //= 16

h_num = ""
for f in f_list[::-1]:
h_num += d_func(f, 2)

return h_num


In the second loop of function dh_func (see above) you use + for appending to a string. This is a inefficient operation in python. There is the string method join() for that task. So we rewrite the function with a better function name to
def to_hex(n):