1
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I have created this simple code:

For the size of an array with 2 values (n and m), verify if n and m are >= 1. m = width and n = height.

The code works but I'm sure it isn't optimized.

printf("Number of ligns.");
scanf("%d",n);
printf("Number of columns.");
scanf("%d",m);


if(*n >= 1)
{
    if(*m >= 1)
    {
        printf("Number of ligns : %x, Number of columns : %x \n", *n, *m);
    }
    else
    {
        while(*m < 1)
        {
            printf("Error, number of colums/ligns < 1. \n");
            scanf("%d",m);
        }
        printf("Number of ligns : %x, Number of columns : %x \n", *n, *m);
    }
}
else
{
    while(*n < 1)
    {
        printf("Error, number of colums/ligns < 1. \n");
        scanf("%d",n);
    }
            if(*m >= 1)
    {
        printf("Number of ligns : %x, Number of columns : %x \n", *n, *m);
    }
    else
    {
        while(*m < 1)
        {
            printf("Error, number of colums/ligns < 1. \n");
            scanf("%d",m);
        }
        printf("Number of ligns : %x, Number of columns : %x \n", *n, *m);
    }
}
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3
  • \$\begingroup\$ The big question is not whether it is optimized. The big question is "Does it matter"? Do you find it too slow? How fast would you like it to be? \$\endgroup\$
    – luiscubal
    Commented Feb 6, 2013 at 19:51
  • \$\begingroup\$ @luiscubal I think this is a learning exercise - and if so, its more about learning how to do it the right way than optimizing for performance. At first glance, I see they are violating the DRY principle. \$\endgroup\$
    – jsanc623
    Commented Feb 6, 2013 at 19:56
  • \$\begingroup\$ Also, this doesn't seem to be the whole function. \$\endgroup\$
    – luiscubal
    Commented Feb 6, 2013 at 19:59

1 Answer 1

5
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You should provide a compiling code. I'll assume that n and m are int, but you should have added their declaration.

  • You should use explicit names for variables. n is a line count, so call it line_count. m is column_count.
  • You should check the return values of scanf to be sure you handle gracefully EOF and bad input.
  • You print "Error, number of colums/ligns < 1. \n" every time, so the user can't know if it's the lines or the columns or both that are < 1.
  • The english word is "lines", not "ligns".
  • Your checks are too complicated and redundants. The entire if/else block can be replaced by this:

    while(*line_count < 1)
    {
        printf("Error, number of lines < 1. \n");
        scanf("%d", line_count);
    }
    
    
    while(*column_count < 1)
    {
        printf("Error, number of colums < 1. \n");
        scanf("%d", column_count);
    }
    
    printf("Number of lines : %x, Number of columns : %x \n", *line_count, *column_count);
    
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2
  • 1
    \$\begingroup\$ Note that n and m don't seem to be the line/col count variables, they are pointers to the count variables. \$\endgroup\$
    – luiscubal
    Commented Feb 6, 2013 at 20:07
  • \$\begingroup\$ Indeed. But I am often reluctant to put some "ptr" prefix or suffix in the names. I had an overdose of hungarian notation several years ago, I try to avoid anything that looks like it. \$\endgroup\$
    – Cyrille Ka
    Commented Feb 6, 2013 at 20:17

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