This is a Find unimplemented tasks task from Rosetta Code:

Given the name of a language on Rosetta Code, find all tasks which are not implemented in that language.

There is already a solution that uses urllib, but I decided to add another one using Requests. I've never worked with this library before and would like my code to get reviewed. Any comments are welcome.

Given the name of a language on Rosetta Code,
finds all tasks which are not implemented in that language.
from functools import partial
from operator import itemgetter
from typing import (Dict,

import requests

URL = 'http://www.rosettacode.org/mw/api.php'
REQUEST_PARAMETERS = dict(action='query',

def unimplemented_tasks(language: str,
                        url: str,
                        request_params: Dict[str, Union[str, int, bool]]
                        ) -> Iterator[str]:
    """Yields all unimplemented tasks for a specified language"""
    with requests.Session() as session:
        tasks = partial(tasks_titles,
        all_tasks = tasks(cmtitle='Category:Programming_Tasks')
        language_tasks = set(tasks(cmtitle=f'Category:{language}'))
        for task in all_tasks:
            if task not in language_tasks:
                yield task

def tasks_titles(*,
                 session: requests.Session,
                 url: str,
                 **params: Union[str, int, bool]) -> Iterator[str]:
    """Yields tasks names for a specified category"""
    while True:
        request = session.get(url, params=params)
        data = request.json()
        yield from map(itemgetter('title'), data['query']['categorymembers'])
        query_continue = data.get('query-continue')
        if query_continue is None:

if __name__ == '__main__':
    tasks = unimplemented_tasks('Python',
    print(*tasks, sep='\n')

Current output for Python:

Calendar - for "REAL" programmers
Catmull–Clark subdivision surface
Checkpoint synchronization
Colour pinstripe/Printer
Compile-time calculation
Constrained genericity
Create an object at a given address
Factorial base numbers indexing permutations of a collection
Fixed length records
Four is the number of letters in the ...
Function prototype
Hilbert curve
Parametric polymorphism
Pattern matching
Peano curve
Rosetta Code/Find bare lang tags
Start from a main routine
Suffixation of decimal numbers
Video display modes
Zeckendorf arithmetic

1 Answer 1


LGTM. Ship it!

There were two minor nits that seemed slightly off:

  1. The use of * in the signature to force kw args is maybe overused, as it covers args that are pretty mandatory.
  2. The print(*tasks, sep='\n') would more naturally be handled by this idiom, which is reusable outside of print(): print('\n'.join(tasks))
  • \$\begingroup\$ Thanks for the review! Yes, keyword-only arguments is still something that I don't have a clear idea about. See my related question: What is the safe way of using keyword-only arguments? I'm accepting the answer but if somebody has something else to propose, feel free to post it. BTW, after I posted this question I came up with a more elegant way to solve the task using mwclient library: link. \$\endgroup\$
    – Georgy
    Commented Nov 28, 2019 at 9:18
  • \$\begingroup\$ Well, if you have a function that uses *args and you're adding args, then they will be kw args, and you'll need a * before them. A function with a tediously large number of ordinary args (say four or more) may benefit from *, if you're concerned the caller might confuse the order switching 3rd & 4th with no possibility of an exception alerting him to the trouble. I really like the @Jerry101 answer you accepted, especially the "dangerous" aspect of this example: def delete(base, *, recursive) \$\endgroup\$
    – J_H
    Commented Nov 28, 2019 at 20:42

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