# Detecting line separators and line breaks in Python CSV [closed]

Here is how I'm detecting a field separator and line break in a CSV file for which I do not already know the format. Does this look sufficient, or are there other things I should be adding here?

SEPARATORS=['\x00', '\x01',  '^', ':', ',', '\t', ':', ';', '|', '~', ' ']
LINE_TERMINATORS_IN_ORDER = ['\x02\n', '\r\n', '\n', '\r']

def get_csv_info(f):
with open(f, 'r') as csvfile:
line = next(csvfile)
dialect = csv.Sniffer().sniff(line, SEPARATORS)
for _terminator in LINE_TERMINATORS_IN_ORDER:
if line.endswith(_terminator):
terminator = _terminator
break
return (dialect.delimiter, terminator)

('\x01', '\x02\n')


Note: using the normal csv.Sniffer without params fails most of the time I use it.

## closed as off-topic by Grajdeanu Alex., Sᴀᴍ Onᴇᴌᴀ, l0b0, Alex L, vnpDec 18 '18 at 23:34

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• SEPARATORS=['\x00', ..., ':', ..., ':',...] - why two :? – Patrick Artner Dec 18 '18 at 6:48
• There is only one case where you need a single byte, which is the line ending with \r. If it doesn't end with it then you need two bytes, no need to go through a list. – ChatterOne Dec 18 '18 at 8:43
• @ChatterOne could you please clarify what you mean with that? For example, what should the LINE_TERMINATORS be instead? – David542 Dec 18 '18 at 16:18