# Given an integer, return its binary representation. You cannot use any Integer.toXXXString methods

Here is my code:

package com.app;

public class Solution {

public String toBinaryString(int n) {
char[] buffer = new char;
for (int i = 0; i < buffer.length; i++) {
buffer[i] = '0';
}
int i = buffer.length - 1;
while (n != 0) {
if (n % 2 != 0) {
buffer[i] = '1';
}
i--;
n >>>= 1;
}
return new String(buffer);
}
}


And I also wrote a few tests:

package com.app;

import org.junit.jupiter.api.Test;

import static org.junit.jupiter.api.Assertions.assertEquals;

class SolutionTest {

@Test
void one() {
Solution solution = new Solution();
assertEquals("00000000000000000000000000000001", solution.toBinaryString(1));
}

@Test
void minusOne() {
Solution solution = new Solution();
assertEquals("11111111111111111111111111111111", solution.toBinaryString(-1));
}

@Test
void intMin() {
Solution solution = new Solution();
assertEquals("10000000000000000000000000000000", solution.toBinaryString(Integer.MIN_VALUE));
}

@Test
void intMax() {
Solution solution = new Solution();
assertEquals("01111111111111111111111111111111", solution.toBinaryString(Integer.MAX_VALUE));
}

@Test
void even() {
Solution solution = new Solution();
assertEquals("00000000000000000000000001111100", solution.toBinaryString(124));
}

@Test
void odd() {
Solution solution = new Solution();
assertEquals("00000000000000000000000000100101", solution.toBinaryString(37));
}
}


The problem seems to be pretty easy. However, it took me some time to make it work with negative numbers and some edge cases. So I'd greatly appreciate if you noticed any bugs in my code.

public static String toBinaryString(int n) {