# Counting results of die rolls

The algorithm bellow is meant to allow a user to roll a die as many times as he would like, then print how many times each side was rolled and how many rolls there were total.

    import java.util.Random;
import java.util.Scanner;

public class DieRoll {

public static void main(String[] args) {
// TODO Auto-generated method stub

int roll;
int totalRolls = 0;
int roll1 = 0;
int roll2 = 0;
int roll3 = 0;
int roll4 = 0;
int roll5 = 0;
int roll6 = 0;
int numberOfRolls;

Scanner scan = new Scanner(System.in);
Random generator = new Random();

System.out.println("How many times would you like to roll? ");
numberOfRolls = scan.nextInt();

for (int numberOfLoops = numberOfRolls; numberOfLoops>0; numberOfLoops--) {

roll = generator.nextInt(6) + 1;
System.out.println("your roll was: " + roll);

switch (roll) {
case 1:
roll1 = roll1 + 1;
break;
case 2:
roll2 = roll2 + 1;
break;
case 3:
roll3 = roll3 + 1;
break;
case 4:
roll4 = roll4 + 1;
break;
case 5:
roll5 = roll5 + 1;
break;
case 6:
roll6 = roll6 + 1;
break;
default:
break;
}
}
System.out.println("\nyou rolled a 1: " + roll1);
System.out.println("you rolled a 2: " + roll2);
System.out.println("you rolled a 3: " + roll3);
System.out.println("you rolled a 4: " + roll4);
System.out.println("you rolled a 5: " + roll5);
System.out.println("you rolled a 6: " + roll6);

System.out.println("\nYou spun a total of : " + numberOfRolls);
}
}


The algorithm can be simplified quite a bit. No need for switch-case. Just create an array (faceCount) with six slots and increment the appropriate slot. In other words:
roll = generator.nextInt(6);

Then to print, iterate over faceCount and display the appropriate values (increment by one to adjust for array indexing).