# Hash Tables: Ice Cream Parlor solution in javascript [closed]

I tried solving the Hash Tables: Ice Cream Parlor question in javascript:

'use strict';

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
inputString += inputStdin;
});

process.stdin.on('end', function() {
inputString = inputString.replace(/\s*$/, '') .split('\n') .map(str => str.replace(/\s*$/, ''));

main();
});

return inputString[currentLine++];
}

// Complete the whatFlavors function below.
function whatFlavors(cost, money) {

// Solution starts here
var dict1={};

var len=cost.length;

for(var i=0; i<len; i++) {

if (cost[i]<money) {
if(dict1[cost[i]] !== undefined)
{
if(Array.isArray(dict1[cost[i]]))
{
dict1[cost[i]].push(i);
}
else
{
dict1[cost[i]] = [dict1[cost[i]]];
dict1[cost[i]].push(i);
}
}
else
dict1[cost[i]] = i;
}
}

cost.sort(function(a,b) {return a-b});

for(var j=0; j<len; j++){
var left=0;
var right=len-1;
if(cost[j]<money){
var ser=money-cost[j];
while(left<right){
var mid=Math.floor((left+right)/2);

if(ser===cost[mid]){
var val1=cost[j];
var val2=cost[mid];
break;
}
if(ser<cost[mid]){
right = mid-1;
}
else{
left = mid+1;
}
}
if(val1 !== undefined && val2 !== undefined ){
break;
}
}
}

var index1;
var index2;
if (val1===val2) {
index1 = dict1[val1][0];
index2 = dict1[val2][1];
}
else{
index1 = dict1[val1];
index2 = dict1[val2];
}

if (index2 > index1) {
console.log(index1+1, index2+1);
}
else{
console.log(index2+1, index1+1);
}
// Solution ends here
}

function main() {

for (let tItr = 0; tItr < t; tItr++) {

const cost = readLine().split(' ').map(costTemp => parseInt(costTemp, 10));

whatFlavors(cost, money);
}
}


It works for all inputs except when it is very large, for example when the input is very large for eg:
30733 39289 12352 19413 448 3955 74 75 12316 34744 2916 4669 1941 6571 2871 17443 34132 42603 1753 9623 7217 8111 3411 17665 3190 16653 1923 14237 6307 22944 10874 22052 967 21913 7562 7948 11038 36319 586 8260 338 1426 17083 37691 11944 15889 10347 13601 643 1653 18754 19595 9561 22822 22521 26308 114 1965 338 412 8423 9497 6371 33551 1292 3705 5634 9563 14043 14669 12566 39425 1149 2638 12664 12939 10217 29104
it simply throws Wrong Answer, is there a better way to write the same script?

## closed as off-topic by Jamal♦Jul 26 '18 at 2:36

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal
If this question can be reworded to fit the rules in the help center, please edit the question.

• The place to go to get help finding problems in your code is stackoverflow.com – Blindman67 Jul 26 '18 at 15:37

The error was because of a silly mistake, in the binary search, it should be while(left<=right):

'use strict';

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
inputString += inputStdin;
});

process.stdin.on('end', function() {
inputString = inputString.replace(/\s*$/, '') .split('\n') .map(str => str.replace(/\s*$/, ''));

main();
});

return inputString[currentLine++];
}

// Complete the whatFlavors function below.
function whatFlavors(cost, money) {
// Solution starts here
var dict1={};

var len=cost.length;

for(var i=0; i<len; i++) {

if (cost[i]<money) {
if(dict1[cost[i]] !== undefined)
{
if(Array.isArray(dict1[cost[i]]))
{
dict1[cost[i]].push(i);
}
else
{
dict1[cost[i]] = [dict1[cost[i]]];
dict1[cost[i]].push(i);
}
}
else
dict1[cost[i]] = i;
}
}

cost.sort(function(a,b) {return a-b});

for(var j=0; j<len; j++){
var left=0;
var right=len-1;
if(cost[j]<money){
var ser=money-cost[j];
while(left<=right){
var mid=Math.floor((left+right)/2);

if(ser===cost[mid]){
var val1=cost[j];
var val2=cost[mid];
break;
}
if(ser<cost[mid]){
right = mid-1;
}
else{
left = mid+1;
}
}
if(val1 !== undefined && val2 !== undefined ){
break;
}
}
}

var index1;
var index2;
if (val1===val2) {
index1 = dict1[val1][0];
index2 = dict1[val2][1];
}
else{
index1 = dict1[val1];
index2 = dict1[val2];
}

if (index2 > index1) {
console.log(index1+1, index2+1);
}
else{
console.log(index2+1, index1+1);
}
// Solution ends here
}

function main() {