I'm looking for the best solution.

Here is a response from server and i need to get Organizations list:

   "code": 0,
   "message": "success",
   "organizations": [
       "organization_id": "10234695",
       "name": "Zillum",
       "contact_name": "John Smith",
       "email": "[email protected]",
       "is_default_org": false,
       "language_code": "en",
       "fiscal_year_start_month": 0,
       "account_created_date": "2016-02-18",
       "time_zone": "PST",
       "is_org_active": true,
       "currency_id": "460000000000097",
       "currency_code": "USD",
       "currency_symbol": "$",
       "currency_format": "###,##0.00",
       "price_precision": 2

Here is my convert method:

var contentJson = await SendRequest(request);
            var contentJo = (JObject)JsonConvert.DeserializeObject(contentJson);
            var organizationsJArray = contentJo["organizations"]

            var organizations = organizationsJArray.ToObject<List<Organization>>();

Code works, but I'm looking for a better Convert Method. Can I do without converting to JArray?

  • \$\begingroup\$ You're not handling errors and corner-cases but, well, that might be OK...is there a specific goal? To me this small snippet looks OK (I have, maybe, just few opinionated minor style comments) but you may have some more specific issues in mind (performance? maintainability?) \$\endgroup\$ Jun 4, 2018 at 9:35
  • \$\begingroup\$ You can use the List<Organization> in the same way as a generic parameter for the DeserializeObject method. There's no need to create the JObject first. \$\endgroup\$
    – t3chb0t
    Jun 4, 2018 at 9:38
  • \$\begingroup\$ @t3chb0t it cannot be convert directly, because root object it's not an Array \$\endgroup\$ Jun 4, 2018 at 10:15
  • \$\begingroup\$ oh, ok, then put it in another object that has a property of this type. \$\endgroup\$
    – t3chb0t
    Jun 4, 2018 at 10:16
  • \$\begingroup\$ @AdrianoRepetti Yeah, thanks a lot. I'm using error handling. I thought that there is a shorter conversion, because I'm not familiar with the methods Newtonsoft.Json \$\endgroup\$ Jun 4, 2018 at 10:23

2 Answers 2


Given that you are already using the ToObject, consider simplifying the code for readability and the advantage of not having to convert anything.

var contentJson = await SendRequest(request);
dynamic response = JsonConvert.DeserializeObject(contentJson); 
List<Organization> organizations = response.organizations.ToObject<List<Organization>>();

The actual response appears to be of no concern so using a dynamic simplifies things. Converting back to strongly typed objects by calling ToObject<T> was a good choice and should work out fine.


Json.Net will (by default) accept missing fields without a problem when doing typed deserialization, so I believe you can do:

class ContentData
    public List<Organization> organizations;


var contentData = JsonConvert.DeserializeObject<ContentData>(contentJson);

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