Get tuple data in an array containing only one element from another tuple

Question

Example: I want to select tuple in an array(t_bet), which contains just one element from judge_tpl = (5,12,24). For example, (3, 4, 5, 16, 30) is ok while (3, 12, 24, 29, 30) is not because it contains two elements.

t_bet = [(3, 12, 24, 29, 30),
 (3, 13, 18, 19, 22),
 (1, 11, 16, 17, 22),
 (3, 4, 5, 16, 30),
 (1, 11, 15, 20, 24)]

lst = []
for i in t_bet:
    if (5 in i) and (12 not in i) and (24 not in i ) :
        lst.append(i)
    elif (5 not in i) and (12 in i) and (24 not in i ):
        lst.append(i)
    elif (5 not in i) and (12 not in i) and (24 in i ):
        lst.append(i)

lst: [(3, 4, 5, 16, 30), (1, 11, 15, 20, 24)]

I have to list all combinations using if..elif,which is inconvenient especially when there are so many elements in judge_tpl.

Notice: The tuples in t_bet have same lengths while there are more than 10 elements in judge_tpl.

Answer 1

1. You don't need parenthesis around the conditions in your if statements

   if x in y and another_x in y is the same as if (x in y) and (another_x in y)

2. Use list comprehensions when possible see PEP8#202

3. Use intersection of sets to get how many elements occur in both tuples

   If duplicated don't matter (as they do not in your code) it is possible to convert the tuples into sets and check if the intersection between the sets are 1 (Meaning there is only 1 element that occurs in both) Like @Maarten Fabré suggested

---

JUDGE = (5, 12, 24)

def valid_bet(bets):
    return [bet for bet in bets if len(set(bet) & set(JUDGE)) == 1]
    # return [bet for bet in best if len(set(bet).intersection(set(JUDGE))) == 1]
    # set_a & set_b == set_a.intersection(set_b)

if __name__ == "__main__":
    bets = [(3, 12, 24, 29, 30),
            (3, 13, 18, 19, 22),
            (1, 11, 16, 17, 22),
            (3, 4, 5, 16, 30),
            (1, 11, 15, 20, 24)]
    print(valid_bet(bets))