Python method to round up to the nearest 10

Question

I am trying to write a program where if I call

get_bin_pos(19.4) ==> output as 20
get_bin_pos(13.4) ==> output as 20
get_bin_pos(31.4) ==> output as 40

I wrote something like below, it looks bad, any suggestion in optimizing it ?

Switch statement for this would be more readable, but we don't have a switch in python. So any other way?

def get_bin_pos(self, value):
        if value <= 10:
            return 10
        if value <= 20:
            return 20
        if value <= 30:
            return 30
        if value <= 40:
            return 40
        if value <= 50:
            return 50
        if value <= 60:
            return 60
        if value <= 70:
            return 70

Answer 1

• If you want to ceil, then you want to use math.ceil. This is as easy as:

  \$10 \lceil \frac{value}{10} \rceil\$

• You may want to make a generic function to ceil within a bound.

• You can set your somewhat weird limits to the function.

import math


def ceil(number, bound=1):
    return bound * math.ceil(number / bound)


def get_bin_pos(value):
    if value > 70:
        return None
    return ceil(max(value, 1), 10)