# Find triangle types

This challenge I am working on involves checking the sides of a triangle and returning the type of triangle as a symbol.

For example, :equilateral if all sides are equal, :scalene if the sides are all different, and :isoseles if two sides are the same.

Here is my thought process: I want to make something that doesn't involve a bunch of if/else or case statements. To achieve this, I thought that using math would help. Now, my math isn't that great, so I had to research cosine and make an algorithm to return angles A,B, and C.

First, I know this isn't required. I don't need the angles, but I thought it would help me avoid too many statements. However, I couldn't figure out what to do after this step.

Below is my code. It works, but I feel like it's kind of tacky. I know I could do better, but I'm facing a wall here. Any input?

def triangle(one, two, three)
is_valid_triangle?(one,two,three)
end

def is_valid_triangle?(one,two,three)
sides = [one,two,three].sort
if (sides + sides <= sides) || (sides == 0)
return "invalid!"
else
which_triangle?(one,two,three)
end
end

def which_triangle?(one,two,three)
triangles = {equilateral: [60,60,60], isosceles: , scalene: }
angle_a = (Math.acos((two**2+three**2-one**2)/(2*two*three).to_f)*180/Math::PI).round(2)
angle_b = (Math.acos((three**2+one**2-two**2)/(2*three*one).to_f)*180/Math::PI).round(2)
angle_c = (Math.acos((one**2+two**2-three**2)/(2*one*two).to_f)*180/Math::PI).round(2)
if angle_a && angle_b == 60
return :equilateral, triangles[:equilateral]
elsif angle_a != angle_b && angle_b != angle_c
triangles[:scalene] = [angle_a, angle_b, angle_c]
return :scalene, triangles[:scalene]
else
triangles[:isosceles] = [angle_a, angle_b, angle_c]
return :isosceles, triangles[:isosceles]
end
end

p triangle(30,23,10)
p triangle(3,3,3)
p triangle(1.5,3,3)
p triangle(3,4,5)
p triangle(0,3,3)
p triangle(3,1,1)

• You seriously think this looks simpler than checking lengths of three sides? It probably takes two lines of code to do it. – Stack crashed Oct 28 '17 at 5:09
• If a==b and b==c: return type1 elif a==b or b==c or a==c: return type2 return type3 – Stack crashed Oct 28 '17 at 5:13
• @Stackcrashed I understand that my way isn't simpler, I'm just trying to figure out a better way to do it without using if, elif statements. Unless there isn't any better way to do it. – Nathan Oct 29 '17 at 1:20
• Please see What to do when someone answers. I have rolled back Rev 3 → 2. – 200_success Oct 29 '17 at 2:55
• Note that @Stackcrashed's method works without elif since you are doing an early return. – user1149 Oct 29 '17 at 16:56

For triangle(3, 2, 3), the resulting classification is wrong:
[:scalene, [70.53, 38.94, 70.53]]