# Refresh webpage on change in folder

I want to refresh my web page every time a file is uploaded to the folder.

I have a web service written in flask having the following handler

@app.route('/getlatest/')
def getlatest():
import os
import glob
newset = max(glob.iglob('static/*'),key=os.path.getctime)


This gives me the name of the latest file in the folder.

I have an Ajax call in my JS (client side) to constantly get data from above function.

function GetLatest()
{
$.ajax({ url: "http://localhost:5000/getlatest", success: function(result) { if(previousName != result){ previousName = result;$("#image").attr("src","/"+previousName);
}
}
});
}


function calling server every second.

(function myLoop (i) {
setTimeout(function () {
GetLatest();
if (--i) myLoop(i);
}, 1000)
})(100);


This Works fine (well almost). My Question is: Is there any better way to do it (there must be)?

I'm open to technology choices what every they may be (node, angualr etc).

• There's no point in importing os and glob inside the function. Local import is used for very specific cases and this is not one of them.
• You're defining newset and then returning newest, did you test your code?
• There's no point in defining newest (after fixing the typo), and then returning it in a separate line. Just return it in one line.
• Add a space before key=..., as per Python conventions.