# Dropdown list of 8 items

I have an input which contains a dropdown list of 8 items. Depending on the option the user picks, I want to change the value of their input into a a different string value. In order to do this, I am using a ton of if else statements, which make this look very bulky and I would like to condense this if at all possible. I have the following code:

if (inputFive == "Corporation"){
inputFive = "534"
}else if (inputFive == "LLC"){
inputFive = "535"
}else if(inputFive == "LLP"){
inputFive = "536"
}else if(inputFive == "Partnership"){
inputFive = "537"
}else if(inputFive == "Sole Proprietorship"){
inputFive = "538"
}else if(inputFive == "Limited Partnership"){
inputFive = "539"
} else {
inputFive = "540"
}


As you can see, this looks a little old-school, and I would like to see if there is a better/simpler way to make this happen. Just looking to condense this code if at all possible. All options/hints will be appreciated!

• This looks like a good example where key/value pairs would come in handy. You could refractor your code to use a dictionary – Ludisposed Jul 7 '17 at 17:18
• @Ludisposed Thank you for your response! Could you please expand on what you mean a little bit more? (maybe what resource to look at and what now). Thanks again. – KV Ghumaan Jul 7 '17 at 17:21

I am not a Javascript programmer, so I will try my best how to explain to use a dictionary. A dictionary means you can add a value to a key

Example from dotnet perls

# Creations of a dictionary
var dictionary = {"Corporation":534,"LLC":535,"LLP":536,"Partnership":537,"Sole Proprietorship":538,"Limited Partnership":539};

# Getting values of dictionary
new_inputFive = dictionary[inputfive]

# For instance when inputfive="LLC" new_inputFive = 535

• Hello and thanks again! I am using JavaScript, not Java. Is this possible in JS? – KV Ghumaan Jul 7 '17 at 17:28
• Sorry my bad. Will edit – Ludisposed Jul 7 '17 at 17:31
• I forgot qoutes around the numbers, and will try to give more information. But unable to edit at the moment since I am busy – Ludisposed Jul 7 '17 at 18:20
• To get the default you could do new_inputFive = dictionary[inputfive] || '540' – Marc Rohloff Jul 7 '17 at 20:58