I'm trying to create a filtered list of objects where each object in the list has both a label and value property.

First I use .pick to select the key/value pairs I want from the initial object, then I iterate over the 'picked' properties and push the key into an object property called label, and push the value of the property into a property called value. I then return the empty array.

function formatToInput(obj, list) {
    var empty = []

    _.forIn(_.pick(obj, list), (val, key) => {
            label: _.startCase(key),
            value: val

    return empty;

// use like so

var test = {blue: 10, green: 5, yellow: 3, pink: 1};
var filter = ['green', 'yellow'];

var results = formatToInput(test, filter)


// [{label: Green, value: 5}, {label: Yellow, value: 3}]

I'm trying to avoid having to manually create an array and pushing objects into it, but I couldn't find a solution (in Lodash) that would allow me to do this.

  • \$\begingroup\$ Is there any chance to have values in filter which are not in test? \$\endgroup\$
    – Tushar
    Commented Jun 21, 2017 at 4:55

1 Answer 1


The code looks like you're passing the processed data to autocomplete.


  • formatToInput: This gives no idea of what the function is doing.
  • empty: Is it really empty at the end of formatToInput?
  • obj, list: Confusing.
  • test, results: Can be named better.


Do you really need a library for this functionality? The Same functionality can be done without Lodash or any other library. If Lodash is only used for this functionality, it can be removed.

Missing Semi-colons

Although, a small thing Automatic Semicolon Insertion can lead to unexpected behavior. The usage of the semi-colon is not consistent. I'll recommend using JSLint/JSHint.


I'll recommend the use of Array#map and String methods to make the first character uppercase.

const colorValueMap = {
  blue: 10,
  green: 5,
  yellow: 3,
  pink: 1
const colors = ['green', 'yellow'];

const result = colors.map(color => ({
  label: color[0].toUpperCase() + color.slice(1),
  value: colorValueMap[color]

Above solution assumes that the value from the filter array always exists in the object. If this is not the case, you can first filter the array and then use map on it.

colors.filter(color => colorValueMap.hasOwnProperty(color)).map(color => ({
  • \$\begingroup\$ Functionally this is a bit different, the original only copies over existing attributes from the filter. You create all attributes regardless, with undefined values when the original object does not have the attribute. Perhaps you could first filter, then map? \$\endgroup\$
    – konijn
    Commented Jun 20, 2017 at 20:57
  • \$\begingroup\$ @konijn True. I've updated the answer. Thanks :) \$\endgroup\$
    – Tushar
    Commented Jun 21, 2017 at 7:58

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