Since I did not get a satisfactory answer here (and I really needed to get it going on this weekend), I decided to implement my own Fisher–Yates shuffle, porting the code I found in other SO posts. I know my programming technique is far from optimal, so I decided to post this here.

What do you think? Can it be improved?

public static JSONArray shuffleJsonArray (JSONArray array) throws JSONException {
    // Implementing Fisher–Yates shuffle
        Random rnd = new Random();
        for (int i = array.length() - 1; i >= 0; i--)
          int j = rnd.nextInt(i + 1);
          // Simple swap
          Object object = array.get(j);
          array.put(j, array.get(i));
          array.put(i, object);
    return array;

1 Answer 1


It runs in \$O(n)\$ time so I'm not sure there's a way to improve this. It looks like you've implemented the algorithm pretty well, according the Fisher-Yates shuffle.

You might consider not using Object if you can use the type that's stored in the array instead.

I also thought I read somewhere that it should be safe to loop to \$n/2\$ instead of \$n\$ (because you're swapping with elements from \$1 \cdots n\$ so in theory, you shouldn't need to swap every element), but I don't have hard proof of that, so you take your chances ;)

  • \$\begingroup\$ Thanks for looking at it. I based it on that wikipedia page and a couple of posts in SO. I will keep in mind the n/2 loops to change it if needed. Lastly, I wrote it using JSONObject instead of Object but then I changed it to make it more reusable. What would be the advantage of using JSONObject instead? \$\endgroup\$
    – Aleadam
    Apr 4, 2011 at 15:30
  • \$\begingroup\$ @Aleadam: I don't know the JSONArray datatype well, I guess I was trying to suggest to use Java generics so you don't have to use Object, but I don't know if you can do that with JSONArray. \$\endgroup\$ Apr 4, 2011 at 15:36
  • \$\begingroup\$ I also think that there is no faster way for shuffling an array. Every try in doing it faster (O(log n) or O(sqrt n)) would result in a poorly shuffled array. \$\endgroup\$
    – leemes
    May 17, 2012 at 20:58

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