Using the array.filter function, I can efficiently pull out all elements that do or do not meet a condition:
let large = [12, 5, 8, 130, 44].filter((x) => x > 10); let small = [12, 5, 8, 130, 44].filter((x) => !(x > 10));
However, in the example above, I'm iterating over the array twice and performing the same test each time. Is there a simple way to generate both 'large' and 'small' in a single pass over the array? In particular, if the callback to evaluate whether an element should be kept is expensive, I'd like to avoid calling it twice.