Here is a functional approach, as alluded to by @Peilonrayz:
def get_numbers_up_to(n, min_=10):
Ask the user for numbers until he enters a number larger than `n`.
Yields all entered numbers larger than `min_`.
num = int(input())
if num > n:
elif num >= min_:
if __name__ == '__main__':
This uses a generator function to
yield the numbers as they come in (if they match the criteria), instead of accumulating them in a list right away.
'\n'.join(str(value) for value in lst) this uses
'\n'.join(map(str, lst)), but this is a matter of taste in Python 3.x (if you like functional programming more, the
map looks nicer).
Other than that, your code does not include any user input validation. (What happens if the user inputs
foo, instead of a number?)
Also, all values are hard-coded, so re-using the code becomes harder. Therefore I made it into a function with parameters.
Note that I used
min_ instead of
min to avoid shadowing a built-in function.
Also, docstrings never hurt nobody.
I also included a
if __name__ == '__main__': guard to allow importing of this function from another module.