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I decided to solve the Box It! challenge in Hackerrank to improve my C++ knowledge as I'm still new to the language.

Design a class named Box whose dimensions are integers and private to the class. The dimensions are labeled: length \$l\$ , breadth \$b\$ , and height \$h\$.

The default constructor of the class should initialise \$l\$ ,\$b\$ ,\$h\$ and to length, breadth and height .

The parameterized constructor Box(int length, int breadth, int height) should initialize Box's \$l\$ , \$b\$ and \$h\$ to length, breadth and height.

The copy constructor Box(Box B) should set \$l\$ , \$b\$ and \$h\$ to \$B\$ 's \$l\$ , \$b\$ and \$h\$ respectively.

Apart from the above, the class should have \$4\$ functions:

  • int getLength() - Return box's length
  • int getBreadth() - Return box's breadth
  • int getHeight() - Return box's height
  • long long CalculateVolume() - Return the volume of the box

Overload the operator for the class Box. Box \$A \leq \$ Box \$B\$ if:

  • \$ A.l \leq B.l\$
  • \$ A.b \leq B.b\$ and \$ A.l == B.l\$
  • \$ A.h \leq B.h\$ and \$ A.b == B.b\$ and \$ A.l == B.l\$

Overload operator \$<<\$ for the class Box().

If \$B\$ is an object of class Box:

\$cout << B\$ should print \$ B.l, B.b \$ and \$B.h\$ on a single line separated by spaces.

Constraints

\$0 \leq l,b,h \leq 10^5\$ Two boxes being compared using the \$<\$ operator will not have all three dimensions equal.

Here is my code

#include<bits/stdc++.h>    
using namespace std;
class Box{

    int length, breadth, height;
    public:
    Box (){
        length =0;
        breadth = 0;
        height =0;
    }
    Box (int l, int b, int h)
    {
        length =l;
        breadth = b;
        height = h;
    }
    Box(const Box& b){
        length =  b.length;
        breadth = b.breadth;
        height =  b.height;

    }
    int getLength(){
        return length;
    }
    int getBreadth (){
        return breadth;
    }
    int getHeight(){
        return height;
    }
    long long CalculateVolume(){
        return (long long) length * breadth * height;
    }

    bool operator<(Box& b){

        if(this->length <= b.length || this->breadth <= b.breadth && this->length == b.length || 

          this->height <= b.height && this->length == b.length && this->breadth == b.breadth)
        {

        return true;
        }
        return false;
    }
    friend ostream& operator<<(ostream &out, const Box &B);

};
         ostream& operator<<(ostream  &out, const Box &B){
         out<< B.length<<" "<< B.breadth<< " " << B.height;
         return out;
    }
void check2()
{
    int n;
    cin>>n;
    Box temp;
    for(int i=0;i<n;i++)
    {
        int type;
        cin>>type;
        if(type ==1)
        {
            cout<<temp<<endl;
        }
        if(type == 2)
        {
            int l,b,h;
            cin>>l>>b>>h;
            Box NewBox(l,b,h);
            temp=NewBox;
            cout<<temp<<endl;
        }
        if(type==3)
        {
            int l,b,h;
            cin>>l>>b>>h;
            Box NewBox(l,b,h);
            if(NewBox<temp)
            {
                cout<<"Lesser\n";
            }
            else
            {
                cout<<"Greater\n";
            }
        }
        if(type==4)
        {
            cout<<temp.CalculateVolume()<<endl;
        }
        if(type==5)
        {
            Box NewBox(temp);
            cout<<NewBox<<endl;
        }

    }
}

int main()
{
    check2();
}

Final thoughts

  • I now I shouldn't be using this line of code using namespace std; as recommended in other reviews but Hackerrank had this pre-defined and I couldn't change it. The Check2() and main() were also predefined as well.

  • Was the use of friend method an overkill?

  • Did I override the operators << and < correctly?
  • How can I improve this code?
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  • \$\begingroup\$ Just an fyi, you can change any of the code that Hackerrank supplies. As long as the code will compile, it will accept it. \$\endgroup\$
    – user33306
    Nov 10, 2016 at 21:30
  • \$\begingroup\$ You need parenthesis on your operator< otherwise the comparisons are made serially \$\endgroup\$ Nov 10, 2016 at 21:30
  • \$\begingroup\$ @tinstaafl the code is in a locked editor and I'm only meant to write a class that will be called by the locked editor \$\endgroup\$
    – Tolani
    Nov 10, 2016 at 21:32
  • \$\begingroup\$ OK. I also noticed the the < operator code only tests < but the description uses <=. \$\endgroup\$
    – user33306
    Nov 10, 2016 at 21:34
  • \$\begingroup\$ I must have changed it whilst copying the code to an editor . Good Spot on . I will make amends \$\endgroup\$
    – Tolani
    Nov 10, 2016 at 21:35

2 Answers 2

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  • The problem statement defines the less than condition differently.

  • I recommend to use tuple<int, int, int> for box dimensions. The default operator< for tuples does exactly what the problem statement asks for.

  • The

    if (condition)
    {
        return true;
    }
    return false;
    

    is a long way to say

    return condition;
    
  • this-> is just a noise. You may safely refer to this->length as length.

  • An indentation for operator<< is confusing, but I assume it a copy-paste error.

  • #include <bits/stdc++.h> is always wrong.

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It's strange to use a signed type for length, but that appears to be imposed on you by the problem statement, so blame a poor specification for that.

Despite the letters std, <bits/stdc++.h> is not a standard header, so you have a portability bug. Even where it exists, it brings in far more than you need, so get used to including just the headers you need.

Avoid using namespace std; - that deprives you of the benefits of namespacing. If you really can't type std:: where needed, then import just the names you need into the smallest reasonable scope:

void check2()
{
    using std::cin;
    using std::cout;
    using std::endl;
    //...
}

Prefer to use initialisers to set members - a good compiler (e.g. g++ -Weffc++) can warn when you forget one:

Box()
    : Box{0, 0, 0}
{
}

Box(int length, int breadth, int height)
    : length{length},
      breadth{breadth},
      height{height}
{
}

We can omit the Box(const Box&) constructor, as the compiler-generated one is identical.

Many methods are missing const qualifiers:

int getLength() const;
int getBreadth () const;
int getHeight() const;
long long CalculateVolume() const;

bool operator<(const Box& b) const;

check2 is a completely meaningless name; choose a name that demonstrates its purpose. Similarly, what does temp mean to the reader?

When reading input, always check the state of the stream afterwards:

if (!(std::cin >> l >> b >> h)) {
    // deal with input error here
}
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