I have an example array like:
array = [1, 2, 3, 4, 5, 6]
Every of this numbers refers to an object that has text property. I want to make sure that every of these object has the same text value. Currently I do it like this:
correct = []
for number in array:
if(object[number].text == "Sample"):
correct.append(number)
if correct.length == array.length:
return True
Is there a more efficient way to do this, like with lambda function or?
You are iterating over the list, and copying elements that have a certain property to the correct list, then checking whether it's of the size of the original list. In other words, you're checking whether all elements fulfill a certain condition, in other words:
return all(object[number].text == "Sample" for number in array)
I needed to make your example more concrete given your text property description using a list of integers.
array = ["Sample", "Sample", "Sample", "None", "Sample", "Sample"]
If you just need to generate a list of elements with a test for each element or property of that element you can neatly create a list comprehension, roughly relating to your code:
correct = [number for number in array if number is "Sample"]
Which returns:
['Sample', 'Sample', 'Sample', 'Sample', 'Sample']
An else is not included, but you could add one for elements not equal to "Sample". Maybe this could include a check of some sort. I am not sure about efficiency improvements, just a more succinct statement.
return falsein your code for example) \$\endgroup\$text != "Sample"and returning false would avoid the need to create and append a collection, then just return true if you make it out of the loop. \$\endgroup\$