Simplest way to write "FizzBuzz" in Rust

Question

Can you write an a simpler Rust fizzbuzz program than I have? Use my output or the spec:

Write a program that prints the numbers from 1 to 100. But for multiples of three print “Fizz” instead of the number and for the multiples of five print “Buzz”. For numbers which are multiples of both three and five print “FizzBuzz”.

to write your program. I want to see if it's possible to write an even simpler program.

fn main() {
    for i in 1..102 {
        match i {
            i if (i % 15 == 0) => { println!("{:?}", "FizzBuzz") },
            i if (i % 3 == 0) => { println!("{:?}", "Fizz") },
            i if (i % 5 == 0) => { println!("{:?}", "Buzz") },
            _ => { println!("{:?}", i) },
        }
    }
}

Answer 1

I think that match is better, you just do not know how to cook it ;)

fn main() {
    for i in 1..102 {
        match (i%3, i%5) {
            (0, 0) => println!("FizzBuzz"),
            (0, _) => println!("Fizz"),
            (_, 0) => println!("Buzz"),
            (_, _) => println!("{}", i)
        }
    }
}

Answer 2

1. I don't think the match adds a lot here (and I love using match). I'd just use chained if-else blocks.

2. There's no need to format a string literal; just put that string in the println! call directly.

3. Use {} for user-facing output; {:?} is for developer-facing output.

4. There's no need for parenthesis around the if condition. Standalone ifs actually have a lint to remove those parenthesis.

---

fn main() {
    for i in 1..102 {
        if i % 15 == 0 { println!("FizzBuzz") }
        else if i % 3 == 0 { println!("Fizz") }
        else if i % 5 == 0 { println!("Buzz") }
        else { println!("{}", i) }
    }
}

Answer 3

Depending on what you mean by 'simple'...

fn main() {
  for i in 1 .. 101 {
    let s = check(i,3,"Fizz").to_string() + check(i,5,"Buzz");
    println!("{}",if s == "" { i.to_string() } else { s });
  }
}

fn check(n: i8, d: i8, s: &str) -> &str
{
  if n % d == 0 { s } else { "" }
}