I have two little projects that I've been working on.

One is to find all palindromes:

function palindrome(str) {
  var replaceStrChr = str.replace(/\W/g,'').replace(/ /g,'').replace(/_/g,'').toLowerCase();
  var arrayifyStr = replaceStrChr.split('').reverse();
  var stringifyStr = arrayifyStr.join('');

  if (replaceStrChr === stringifyStr){
    return true;
  } else {
    return false;

And the other one is to find the longest word in a string:

function findLongestWord(str){
    var arrayify = str.split(' ');
    var longest = 0;

    for(var x = 0; x < arrayify.length; x++){
        if (arrayify[x].length > longest){
            longest = arrayify[x].length;
    return longest;

What I'm looking for is a better way to do these, shortcuts, better syntax, etc.


2 Answers 2


For the palindrome:

  • You can probably just use one replace operation, but with a more extensive regex. My regex is rusty but something like /[\W_\s]/g could do.

  • split, reverse and join could possibly be just one chain.

    var reversedString = replaceStrChr.split('').reverse().join('');
  • Comparisons are essentially boolean values. You can simply do:

    return replaceStrChr === stringifyStr;

For the longest word:

  • Use reduce and carry through the longest word.

    var longestWord = str.split(' ').reduce(function(prev, next){
      return next.length > prev.length ? next : prev;
  • str doesn't tell me what the string contains. Only when I saw split(' ') did I realize it was a space-separated string. Rename the variable to show its purpose.

  • \$\begingroup\$ length > prev.length ? next : prev; ternary? \$\endgroup\$
    – 13aal
    Commented Apr 29, 2016 at 12:10
  • \$\begingroup\$ @13aal Yes, that's a ternary. \$\endgroup\$
    – Joseph
    Commented Apr 29, 2016 at 12:48
  • \$\begingroup\$ Okay, thank you for the examples and the advice. \$\endgroup\$
    – 13aal
    Commented Apr 29, 2016 at 18:45

I pretty much second everything in @Joseph the Dreamer's answer except for simplifying the palindrome.

You can simplify the regex by making it just /[\W_]/g. So, we now can get the reduced string. We do not need to check for white spaces since those are non-word characters (\W).

replaceStrChr = str.replace(/[\W_]/g, '');

Then there is no need to reverse the string then compare them. We can save time by checking it at the same time:

for(var i = 0, j = replaceStrChr.length; i < j;)
    if(replaceStrChr[i++] !== replaceStrChr[j--]) return false;
return true;

Hope this helps!

  • \$\begingroup\$ That's a really good idea, thanks for this \$\endgroup\$
    – 13aal
    Commented May 1, 2016 at 15:46

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