Problem Statement: We have \$N\$ sticks. The size of the \$i\$th stick is \$A_i\$. We want to know the number of different types of triangles created with each side from a single different stick. Calculate the number of acute triangles, right triangles and obtuse triangles.

Input Format: The first line contains \$N\$. The second line contains \$N\$ integers. The \$i\$th number denotes \$A_i\$.


  • For full score: \$3 \le N \le 5000\$
  • For 40% score: \$3 \le N \le 500\$

For all test cases:

  • \$1 \le A[i] \le 10^4\$
  • \$A[i] \lt A[i+1]\$ where \$1 \le i \lt N\$

Output Format: Print 3 integers: the number of acute triangles, right triangles and obtuse triangles, respectively.

My Solution: My code runs in the given time for small \$n\$ (~500). It will work for large \$n\$ (~5000) but I get time limit exceeded error on the Online Judge.

using System;

namespace CodeStorm
    class Triangles
        static void Main(string[] args)
            int n = int.Parse(Console.ReadLine());
            string[] A_temp = Console.ReadLine().Split(' ');
            int[] A = Array.ConvertAll(A_temp, Int32.Parse);
            int[] A_sq = new int[n];

            for (int i = 0; i < n; i++)
                A_sq[i] = A[i] * A[i];

            int n_m_2 = n - 2;
            int n_m_1 = n - 1;

            int acute = 0, right = 0, obtuse = 0;
            for (int i = 0; i < n_m_2; i++)
                for (int j = i + 1; j < n_m_1; j++)
                    int k = j + 1;
                    int AiPlusAj = A[i] + A[j];

                    while (k < n)
                        int squareSum = A_sq[i] + A_sq[j];
                        if (AiPlusAj <= A[k])
                        else if (squareSum > A_sq[k])
                        else if (squareSum < A_sq[k])
            Console.WriteLine(acute + " " + right + " " + obtuse);

The above code runs perfectly and finds the possible triangles.


2 3 9 10 12 15


2 1 4

The possible triangles are:

Acute triangles: 10−12−15, 9−10−12

Right triangle: 9−12−15

Obtuse triangles: 2−9−10, 3−9−10, 3−10−12, 9−10−15

I want to know a more efficient way to approach the problem so that I can get it executed in the given time limit for \$n\$ (~5000). After I tried to find the complexity, I came up with \$O(n^3)\$. I am not good with complexities. I might be wrong. I would like a more efficient way for the problem.


Sort your sticks by length; square them when already sorted. Then replace the innermost loop with 3 binary searches. In pseudocode,

        max_obtuse = upper_bound(A[j:n], A[i] + A[j])
        max_right = upper_bound(A_sq[j:n], A_sq[i] + A_sq[j])
        max_acute = lower_bound(A_sq[j:n], A_sq[i] + A_sq[j])

        obtuse += max_obtuse - max_right
        right += max_right - max_acute
        acute += max_acute - j

That reduces the execution time from \$O(n^3)\$ to \$O(n^2\log n)\$.


In the sorted array below, values marked as - are strictly less, and values marked as + are strictly greater, than X:

         ^                ^
         |                This is upper bound of X
         This is lower bound of X
|improve this answer|||||
  • \$\begingroup\$ Sir I am new to algorithm. I didn't understand the pseudo code. What do you mean by upper bound and lower bound binary searches. I am sorry if I sound weird. But I am not able to understand the code. \$\endgroup\$ – Aman Ahuja Oct 30 '15 at 17:29
  • \$\begingroup\$ @AmanAhuja See edit. \$\endgroup\$ – vnp Oct 30 '15 at 19:45
  • \$\begingroup\$ First of all thank you so much. That helped me a lot. It improved my code. The code was submitted for a problem on hackerearth. Earlier I cleared 8 out of 16 cases(due to TLE). With your help I could do another 4. The 4 remaining cases are still showing a TLE error. Is there any way to reduce the execution time further. I am using C#. Is it a problem with the language. The execution time has to be within 3s. Thank you anyways. \$\endgroup\$ – Aman Ahuja Oct 31 '15 at 13:14

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