The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be:
1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ...
Let us list the factors of the first seven triangle numbers:
1: 1 3: 1,3 6: 1,2,3,6 10: 1,2,5,10 15: 1,3,5,15 21: 1,3,7,21 28: 1,2,4,7,14,28 We can see that 28 is the first triangle number to have over five divisors.
What is the value of the first triangle number to have over five hundred divisors?
Here is my code :
package coderbyte;
public class Java {
public static void main(String[] args) {
long start = System.nanoTime();
int number = 0;
int index = 0;
boolean found = false;
while (!found) {
int counter = 0;
index++;
number = index * (index + 1) / 2;
for (int i = 1; i * i <= number; i++) {
if (number % i == 0) {
counter = (number % i == i ? counter + 1 : counter + 2);
if (counter > 500) {
found = true;
break;
}
}
}
}
System.out.println(number);
System.out.println(System.nanoTime() - start);
}
}
Any tips on how to improve the runtime and possible shorten the code.
n % i == i
will only occur for index=1 - so it's not necessary to consider. \$\endgroup\$n / i == i
. \$\endgroup\$