Problem description:
The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832.
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
How to Find the Largest product in a Series
Review 1
def greatest_product(n):
numbers=[int(value) for value in n]
result=[reduce(lambda x,y: x*y, islice(numbers, i, i+5), 1) for i in range(len(numbers)-4)]
return max(result)
Review 2
def greatest_product(s, m=0):
for i in range(0, len(s)-4):
m = max(m, prod(map(int,s[i:i+5])))
return m
My Solution
This is my solution for problem 8 of Project Euler using Python:
adjacent_length = 13
largest_product = 0
for i in range(0, len(s) - adjacent_length + 1):
product = 1
for j in range(i, i + adjacent_length):
product *= int(s[j: j + 1])
if product > largest_product:
largest_product = product
How could my code be improved?