I'm posting my C++ code for LeetCode's LRU Cache. If you have time and would like to review, please do so. Thank you!
Problem
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
put(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
The cache is initialized with a positive capacity.
Follow up:
- Could you do both operations in O(1) time complexity?
Example:
LRUCache cache = new LRUCache( 2 /* capacity */ ); cache.put(1, 1); cache.put(2, 2); cache.get(1); // returns 1 cache.put(3, 3); // evicts key 2 cache.get(2); // returns -1 (not found) cache.put(4, 4); // evicts key 1 cache.get(1); // returns -1 (not found) cache.get(3); // returns 3 cache.get(4); // returns 4
Accepted C++
#include <list>
#include <unordered_map>
class LRUCache {
public:
const int size;
std::list<size_t> lru;
std::unordered_map<int, std::list<size_t>::iterator> cache;
std::unordered_map<int, int> key_val_map;
LRUCache(const int capacity) : size(capacity) {}
// Getter constant memory
int get(int key) {
if (key_val_map.count(key) == 0) {
return -1;
}
update(key);
return key_val_map[key];
}
// Setter constant memory
const void put(int key, int value) {
if (key_val_map.size() == size && key_val_map.count(key) == 0) {
clear();
}
update(key);
key_val_map[key] = value;
}
// Add a new key
const void update(int key) {
if (key_val_map.count(key)) {
lru.erase(cache[key]);
}
lru.push_front(key);
cache[key] = lru.begin();
}
// Erase cache
const void clear() {
key_val_map.erase(lru.back());
cache.erase(lru.back());
lru.pop_back();
}
};
Reference
On LeetCode, there is a class usually named Solution
with one or more public
functions which we are not allowed to rename.