I know there must be an easier way to write this but I'm stuck in over-complicating mindset instead of just following the Zen of Python, please enlighten me to the ways of simplicity...

Given a day of the week encoded as 0=Sun, 1=Mon, 2=Tue, ...6=Sat, and a boolean indicating if we are on vacation, return a string of the form "7:00" indicating when the alarm clock should ring. Weekdays, the alarm should be "7:00" and on the weekend it should be "10:00". Unless we are on vacation -- then on weekdays it should be "10:00" and weekends it should be "off".

alarm_clock(1, False) → '7:00'
alarm_clock(5, False) → '7:00'
alarm_clock(0, False) → '10:00'

This is my code:

def alarm_clock(day, vacation):
    
    weekend = "06"
    weekdays = "12345"
    if vacation:
        if str(day) in weekend:
            return "off"
        else:
            return "10:00"
    else:
        if str(day) in weekend:
            return "10:00"
        else:
            return "7:00"

I know there must be an easier way to write this but I'm stuck in over-complicating mindset instead of just following the Zen of Python. Please help me simplify this.

Given a day of the week encoded as 0=Sun, 1=Mon, 2=Tue, ...6=Sat, and a boolean indicating if we are on vacation, return a string of the form "7:00" indicating when the alarm clock should ring. Weekdays, the alarm should be "7:00" and on the weekend it should be "10:00". Unless we are on vacation -- then on weekdays it should be "10:00" and weekends it should be "off".

alarm_clock(1, False) → '7:00'
alarm_clock(5, False) → '7:00'
alarm_clock(0, False) → '10:00'

def alarm_clock(day, vacation):
    
    weekend = "06"
    weekdays = "12345"
    if vacation:
        if str(day) in weekend:
            return "off"
        else:
            return "10:00"
    else:
        if str(day) in weekend:
            return "10:00"
        else:
            return "7:00"