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Jan 12, 2015 at 16:41 comment added RBarryYoung I'm pretty sure that if all you care about is the number of primes below N, it can be done in O(Sqrt(N) log(Sqrt(N)).
Jan 12, 2015 at 11:36 comment added Veedrac To get \$\mathcal{O}(n \log n)\$ time, you'll need to use a sieve.
Jan 12, 2015 at 10:56 answer added 200_success timeline score: 5
Jan 12, 2015 at 10:48 history edited 200_success CC BY-SA 3.0
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Jan 12, 2015 at 8:33 vote accept Rodolfo Dias
Jan 12, 2015 at 8:20 answer added Heslacher timeline score: 8
Jan 12, 2015 at 8:06 history edited Heslacher CC BY-SA 3.0
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Jan 12, 2015 at 7:56 review First posts
Jan 12, 2015 at 8:06
Jan 12, 2015 at 7:53 history asked Rodolfo Dias CC BY-SA 3.0