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Mast
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41 = 2 + 3 + 5 + 7 + 11 + 13\$41 = 2 + 3 + 5 + 7 + 11 + 13\$

41 = 2 + 3 + 5 + 7 + 11 + 13

\$41 = 2 + 3 + 5 + 7 + 11 + 13\$

Problem Statement

The prime 41, can be written as the sum of six consecutive primes:

41 = 2 + 3 + 5 + 7 + 11 + 13

This is the longest sum of consecutive primes that adds to a prime below one-hundred.

The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953.

Which prime, below one-million, can be written as the sum of the most consecutive primes?

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Problem Statement

The prime 41, can be written as the sum of six consecutive primes:

41 = 2 + 3 + 5 + 7 + 11 + 13

This is the longest sum of consecutive primes that adds to a prime below one-hundred.

The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953.

Which prime, below one-million, can be written as the sum of the most consecutive primes?

Code


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Peilonrayz
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Project Euler #50 Efficiency50: Consecutive prime sum

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Arber
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