Revisions to Printing staircase revisited

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edited Feb 28, 2020 at 20:40

No need to declare loads of variables.

`functionfunction staircase(n) {
    let a = "#";
    for(let i =1;i<=n;i++){
        console.log(" ".repeat(n-i)+a.repeat(i))
    }
}`

No need to declare loads of variables.

`function staircase(n) {
let a = "#";
for(let i =1;i<=n;i++){
        console.log(" ".repeat(n-i)+a.repeat(i))
    }
}`

No need to declare loads of variables.

function staircase(n) {
    let a = "#";
    for(let i =1;i<=n;i++){
        console.log(" ".repeat(n-i)+a.repeat(i))
    }
}

deleted 25 characters in body

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edited Feb 28, 2020 at 20:32

Hi here is a very short wayNo need to solve the problem hope it helpsdeclare loads of variables.

`function staircase(n) {
let a = "#";
for(let i =1;i<=n;i++){
        console.log(" ".repeat(n-i)+a.repeat(i))
    }
}`

Hi here is a very short way to solve the problem hope it helps.

`function staircase(n) {
let a = "#";
for(let i =1;i<=n;i++){
        console.log(" ".repeat(n-i)+a.repeat(i))
    }
}`

No need to declare loads of variables.

`function staircase(n) {
let a = "#";
for(let i =1;i<=n;i++){
        console.log(" ".repeat(n-i)+a.repeat(i))
    }
}`

Source Link

created Feb 28, 2020 at 20:15

Hi here is a very short way to solve the problem hope it helps.

`function staircase(n) {
let a = "#";
for(let i =1;i<=n;i++){
        console.log(" ".repeat(n-i)+a.repeat(i))
    }
}`

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