I'm afraid just about everybody who read this question has misunderstood it. I'm not trying to find the best way of printing a vector. I'm trying to find the best way of excluding part of an operation from the last iteration in a loop. I'm seeking advice about a pattern that is repeated is many different contexts. For this reason, I cannot provide a concrete example.
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A well-formed comma-separated list has commas after all but the last element. This means that when dealing with these lists, the comma has to be dealt with on all but the last iteration. This is how I do things currently:
for (auto e = vec.cbegin(); e != vec.cend(); ++e) {
// code that has to be executed for every element
std::cout << *e;
if (e != vec.cend() - 1) {
// code that must not be executed for the last element
std::cout << ", ";
}
}
There are five instances of the above pattern in the project that I'm working on. I feel like there might be a more elegant way of doing this. An alternative that I've come up with is this:
// infinite loop if vec is empty
if (!vec.empty()) {
for (auto e = vec.cbegin(); e != vec.cend() - 1; ++e) {
// code that has to be executed for every element
std::cout << *e;
// code that must not be executed for the last element
std::cout << ", ";
}
// code that has to be executed for every element
std::cout << vec.back();
}
This alternative is slightly faster because there isn't an if in the body but that's not a big deal. The if is true for all but the last iteration so the branch predictor will probably only miss on the last iteration. I also have to repeat code that has to be executed for every element which means that I need to hoist that into a function.
The first snippet is the best that I can come up with but I feel like this could be done better. Note that writing to std::cout is just an example.
